the actual power
72kVA
Power is voltage times current.
usually power source where power comes from logic gates outputs are commonly called source or sink say the power source to the package is positive (VCC is +5) to call the output a source we would use an NPN transistor with the collector connected to +5V the base goes to the logic the emitter is the output terminal the output is the source of +5v sink output would have the emitter grounded base to logic the collector is the output so the output will sink positive voltage to ground A BUFFER usually has two output transistors one for source one for sink and can do either or both
Nothing will happen to the possible output power of the power source i.e it will not increase. Each power source has its maximum possible output power. Adding more lamps in parallel will result in a drop in the circuit's total resistance which causes the total current drawn by the lamps to increase. Your wires might be burnt as a result so be careful.
Simply put, friction reduces output force. The more friction there is, the less effectively power will be delivered, and this results in reduced output force.
The output power of a light source is directly related to the intensity of light it emits. As the intensity of light increases, the output power of the light source also increases. This relationship is important in determining the effectiveness of a light source in various applications, such as in phototherapy or communication systems.
You measure it with a clamp-on ammeter.
Transmission line efficiency is power at the recieving-end of the line compared to the power at the sending-end of the line and is expressed as a percentage, so this can be formulated. % efficiency = load power (output) / source power (input) x 100 In the line, there are power losses. to calculate this we use the formula: power loss = 3.I2.R where I is current and R is resistance. Now that we have the losses, we know the difference between the input and the output. So, for example, if one had the output value known, then to get the input we just add the loss to the output or if had the input known, just subtract the loss from it to get the output. hope that helps
here, the power required by the receiver is the output power and that required from the source is input power. Gain in dB=10 log(output power/input power) we have, loss in dB = -gain in dB = 10 log(input power/output power) or, 50 = 10 log(input power/10nW) or, anti-log(5) = input power/10 nW so the power required from the source is antilog(5)*10nW = 1 mW
Electricity has three terms. Active power - Watt. Apparent power VA, reactive power VAR. Watt is known as active output
When the load resistance (RL) changes, it affects the Norton or Thevenin equivalent circuit by altering the output voltage and current delivered to that load. For a Thevenin equivalent, the output voltage can change based on the voltage divider effect, while for a Norton equivalent, the output current will vary according to the current division principle. This means that the values of the equivalent voltage source (Vth) or current source (In) remain constant, but the load will experience different voltage and current levels depending on its resistance. Consequently, the overall power delivered to the load will also change.
The source and load must be matched to each other and to the transmission line to minimize reflected power. Matching incorrectly can result in very low output power (because a large portion of it is reflected back to the source), and potentially damaging equipment at the source due to overvoltages (from the reflected power).