This question can be addressed by simple calculus. As time (t) passes, the radius (r) of the circle increases at 4 feet per second. dr/dt = 4 The area of the circle is equal to pi multiplied by the square of the radius: A = pi x r2 From which we can infer that dA/dr = 2pi x r The radius, then, changes by four feet for every passing second. In turn, the area is increasing at a given moment by (2pi x r) square feet for every added radial foot. If we multiply square feet per footby feet per second we obtain square feet per second, as required by the question. This is the chain rule of differentiation.
dA/dt = dA/dr x dr/dt = 4 x 2pi x r = 8pi x r If r = 10 feet, then the area is momentarily increasing at 8pi x 10 = 80pi = 251 square feet per second.
Atomic radius increases with increasing period number (= going down) within the same group.
where do you move if the atomic radius increases?
The number of energy levels increase within a group. Therefor the atomic radius increases. So the atomic volume also increases.The atomic radius also increases in a group.For metals, reactivity increases down the group. For non-metals, reactivity decreases down a group.
in the same period, as the atomic number increases, the atomic radius decreases. in the same group, as the atomic number increases, the atomic radius increases.
atomic radius increases down a group as the number of shells increases
For circular motion, linear speed = angular speed (in radians) x radius. How the radius affects speed depends what assumptions you make about the problem. For example, if you assume the radius increases but the angular speed does not, then of course the linear speed will increase.
potassium has a larger atomic radius than sodium because it has more electrons and thus can not hold the outer ones as firmly as sodium, as a general rule Atomic Radius increases on the periodic table increasing from right to left and also increasing from top to bottom
Given a constant velocity v, a radius r, the equation for the period T is given as:T = 2πr/vSo, as radius r increases, so does the period T.
On the periodic table, ionization energy increases moving left to right within a period and up within a group. It decreases as the atomic radius increases in size.
The radius of a cylinder is half the thickness of its circular cross section.
A football field is rectangular, therefore there is no radius. If it were a circular shape then it would have a radius.
The answer to this question is as radius increases shielding affect increases
The radius increases
The atomic radius of elements increases as you go down a group. This increase in radius as you go down a period is primarily caused by the increasing principal quantum number of the outer electron shells.
The circumference of a circle increases with an increase in the radius as it is directly proportional its radius.
As you go across a period, radius shrinks because you are adding protons. The added positive charge increases pull on the electron shells. As you go down a group, radius gets larger because you are increasing shells of electrons. This increases shielding of the nucleus' positive charge, so the electrons are not pulled in as much.
The periodic table is arranged in order (across and down the rows) in increasing number of protons in the nucleus; as the number of proton increases the radius of the nucleus generally increases - thus the order is the order reading down group 2: beryllium (least), magnesium, calcium, strontium, barium and radium (largest).
The volume increases faster. (proportional to the cube of the radius)The surface area increases slower. (proportional to the square of the radius)
In general, atomic radius increases as atomic number increases as electrons are added to the shells farther to the nucleus.
Sodium. Because, down a group the radius increases as the number of shells / orbitals increases.
The radius increases as the number of protons and neutrons increases.
Overall as atomic number increases covalent radius increases.
if the speed is increasing at 3 m/s2 then that is the acceleration (if i understand the question correctly)