sine
The sine.
This ratio is called the sine ratio for a right triangle. A simple way to remember this is by using the mnemonic 'SOHCAHTOA', where SOH stands for sine equals the ratio opposite side/ hypotenuse, COH is cosine equals adjacent side/hypotenuse, and TOA is tangent equals opposite side/adjacent side.
the opposite
If you have an angle then the length of the side OPPOSITE that angle divided by the length of the HYPOTENUSE. (O/H) (HYPOTENUSE is the side opposite the 90 degree angle) or (y/x) and a lot of other cool ways.
(1/2) x (length of the hypotenuse) x sqrt(3)
hypotenuse.
The sine.
Hypotenuse
Yes... opposite an angle of a right triangle to the length of the triangle's hypotenuse.
This ratio is called the sine ratio for a right triangle. A simple way to remember this is by using the mnemonic 'SOHCAHTOA', where SOH stands for sine equals the ratio opposite side/ hypotenuse, COH is cosine equals adjacent side/hypotenuse, and TOA is tangent equals opposite side/adjacent side.
In a right angles triangle the sides are named the hypotenuse (the side opposite the right angle) and the other two sides are called the adjacent and the opposite sides. 1) The sine of an angle = length of the opposite side ÷ length of the hypotenuse. 2) The cosine of an angle = length of the adjacent side ÷ length of the hypotenuse. Using 1) The length of the hypotenuse = length of the opposite side ÷ the sine of the angle. Using tables or a calculator obtain the sine of the angle and divide this into the length of the opposite side. The result will be the length of the hypotenuse.
sin θ : 1 = the length of opposite side to angle θ : the length of the hypotenuse
sine
Sine
Rearrange the sine ratio of sine = opposite/hypotenuse: hypotenuse = opposite/sine hypotenuse = 12/sine 30 degrees = 24 Therefore the hypotenuse is 24 units in length.
You get the sine of the angle. For a right triangle: sin (x) = opposite/hypotenuse cos (x) = adj./hypotenuse tan (x) = opposite/adj
opposite/hypotenuse = sin(x) adjacent/hypotenuse = cos(x) opposite/adjacent = tan(x) where 'x' is the angle in question.