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The specific heat of lead is 128 kg degrees Celsius How much heat is needed to raise the temperature of a kg sample of lead by 10 degrees Celsius?
Wiki User
∙ 7y ago
The relevant equation behind this problem is
Q=m*c* ΔT
Where Q is the energy that must be added to or taken from the system, m is the mass of the object, c is the objects specific heat, and ΔT is the change in temperature in Celsius or Kelvin. Plugging in the given values we get that
Q=.015kg * 128J/(kg*C) * 10C=19.2J.
Therefore, you need 19.2 joules of heat in order to raise the temperature of a .015kg sample of lead by 10 degrees Celsius.
Ignacio Green
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The specific heat of lead is 128 kg degrees Celsius How much heat is needed to raise the temperature of a 0.015kg sample of lead by 10 degrees Celsius?
The relevant equation behind this problem is Q=m*c* ΔT Where Q is the energy that must be added to or taken from the system, m is the mass of the object, c is the objects specific heat, and ΔT is the change in temperature in Celsius or Kelvin. Plugging in the given values we get that Q=.015kg * 128J/(kg*C) * 10C=19.2J. Therefore, you need 19.2 joules of heat in order to raise the temperature of a .015kg sample of lead by 10 degrees Celsius.
