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you need the mass and radius of the sphere- density = mass divided by volume, so mass/volume. the volume of a sphere is 4 divided by 3 multiplied by pi multiplied by the radius squared. 4/3(π)(r^2).
The location of an object's center of gravity depends on the object's shape, and on how its mass is distributed throughout its shape, but not on its size. The center of gravity of a homogeneous sphere is at the center of the sphere, no matter whether the sphere's radius is 1 millimeter or 1 light year.
Density is calculated as mass divided by volume.To get the total mass, add the masses of the individual worlds.To get the volume, use the formula for a sphere. Presumably it would coalesce into a sphere.Finally, divide the mass by the volume.
Pressure = Force / AreaAssuming you have created a force by hanging a certain mass from one hemisphere thenForce = Mass * GravityWe need to consider the area on which the air pressure is acting upwards and supporting the mass. We could look at all of the vectors acting inwards on the lower half of the sphere, but this can be resolved to the same pressure acting upwards over the area across the centre of the sphere - so we take the area as the Cross Sectional Area across the join.Area = PI * radius^2So to calculate the pressure use:Pressure = (Mass*Gravity) / (PI * radius^2)
Yes. For example, the center of mass of a hollow sphere would be at the empty center of that sphere.
Density = mass / volume. You have the density of aluminum and the mass of the aluminum sphere. The volume of a sphere is 4/3*Pi*r^3. Therefore volume = 4/3*Pi*r^3 = mass / density. Solve for r, which is the radius of the sphere.
The mass of a sphere is 4/3*pi*r3*d where r is the radius of the sphere and d is the density of the material of the sphere.
you need the mass and radius of the sphere- density = mass divided by volume, so mass/volume. the volume of a sphere is 4 divided by 3 multiplied by pi multiplied by the radius squared. 4/3(π)(r^2).
mass moment of inertia for a solid sphere: I = (2 /5) * mass * radius2 (mass in kg, radius in metres)
Vol(3)/Vol(2.5) = 33/2.53 = 1.23 So Mass(3) = 1.23*Mass(2.5) = 1.23*500 = 864 grams
The diameter of the sphere is 19.6 cm.
Volume of a sphere = 4/3*pi*radius3 Surface area of a sphere = 4*pi*radius2
Density = mass/ volume volume= 4/3(pie)(r^3) ***r= radius in meters** so find volume then divide mass by volume and there you go.
Yes. If the sphere is homogeneous ... meaning that every speck of it has the same mass, density, etc. ... then it turns out that at any point inside the sphere, all the mass outside that radius cancels out. The sphere acts as if the outside part doesn't exist, and the gravitational field is what you'd expect from only the part of the sphere that's inside that radius.
Mass is conserved which means that a body will have the same mass wherever it goes. But at the centre of a masive sphere the body has no gravity acting on it so its weight is zero. At an intermediated radius the force on it is obviously less than at the surface, and Isac Newton proved that a body at a given distance inside a sphere feels a gravitational force from a sub-sphere of radius equal the distance of the body from the centre. In other words the body feels no gravity from the shell outside its own radius.
First and foremost, you must know the density. Mass is the product of volumeand density (m=vd). Also, a sphere is specified by its radius alone. The "length"of a sphere should represent nothing more than its diameter, which is twice itsradius.==============================Answer #2:First of all, that's no sphere, since spheres don't have 'length'.Next . . . As written, the question has no answer, simply because the mass ofa sphere doesn't depend on its size. A hundred spheres can easily all have thesame size but a hundred different masses.
Provided they are the same thickness, the larger sphere will have a radius of 10.165cm