The two consecutive negative odd integers having 74 as the sum of their squares are -5 and -7.
The sum of the squares of two consecutive positive even integers is 340. Find the integers.
The integers are 5 and 7.
There is no solution.Consecutive negative integers will always add up to a negative number. 110 is positive.
42 + 52 = 16 + 25 = 41
They are -10 and -9.
The integers are -2, -1, 0 and 1.
13 and 14. Also negative 13 and negative 14.
Two negative consecutive odd integers that have a product of 63 are -7 and -9. -7 is larger than -9. -7 is the answer.
9 and 11 92 = 81 112 = 121 81+121 = 202
4, 5 & 6 (16 + 25 + 36)
find the two consecutive odd integers with a sum of 152
The negative part is just a trick because any number squared, whether positive or negative, will turn out to be a positive number. But, to satisfy the question... -6*-6=36 -8*-8=64 36+64=100 tada. -6 and -8 would be the answer.
-9 or -10Two consecutive negative integers that can be multiplied together with a product of 90 would be -9 and -10. A number sentence for this equation would be: -9 X -10 = 90.
9240 is the product of the three consecutive integers 20, 21, and 22.
find three consecutive integers whose sum is - 93
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
The integers are 41, 42 and 43. Also, using consecutive even integers, you find: 40, 42 and 44.
First, we are not interested for the sign of the numbers, because the product of two negative numbers is always positive, so we need to find the two consecutive factors of 240, which are 15 and 16. Thus, the numbers are -16 and -15.
The product of two consecutive integers is 132. Find the two integers. They are: 11*12 = 132