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Since the average of the three integers will be 114/3 = 38, and the three numbers are consecutive, the numbers will be 36, 38 and 40.
Another way to do this problem using algebra is to let the first integer be n, then the next two are n+2 and n+4. Their sum is 3n+6 and it equals 114
So 3n+6=114 and
3n=108
so n=36
then next two numbers must be 38 and 40 since they are consecutive even integers.
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What is the sum of the three consecutive integers that equals 114?
The integers are 37, 38 and 39.
4 consecutive even integers whose sum is -114?
118
What three consecutive numbers add up to 114?
114/3 = 38, so the three integers are 37, 38 and 39.
What integers are four consecutive integers whose sum is 114.?
27 + 28 + 29 + 30 = 114
The sum of three consecutive integers is -114 What are the integers?
Let the integers be x, (x+1) and (x+2) Since, x+(x+1)+(x+2) = -114, by solving the equation for x, we get that, x = -37 Hence the integers are -37, -36 and -35
Consective even integers Find three consective integers whose sum is 114?
The consecutive odd integers for 114 are 37, 38 and 39.
What is the sum of the three consecutive integers that equals 114?
The integers are 37, 38 and 39.
4 consecutive even integers whose sum is -114?
118
What is the sum of two consecutive even integers is 114?
The numbers are 56 and 58.
What three consecutive numbers add up to 114?
114/3 = 38, so the three integers are 37, 38 and 39.
What is the larger of two consecutive even integers if their sum is 226?
The larger is 114, and the other is 112.
What integers are four consecutive integers whose sum is 114.?
27 + 28 + 29 + 30 = 114
What are 4 consecutive integers for 114?
27 + 28 + 29 + 30 = 114
Find 3 consecutive even integers whose sum is -114?
117
The sum of three consecutive integers is -114 What are the integers?
Let the integers be x, (x+1) and (x+2) Since, x+(x+1)+(x+2) = -114, by solving the equation for x, we get that, x = -37 Hence the integers are -37, -36 and -35
What are 4 consecutive integers whose sum is 114?
The integers are 27, 28, 29 and 30.
What is three consecutive integers whose sum is 117?
Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38
