75% of the time, yes
52 weeks and that makes 365 days a year or 365 1/4 days on leap year. that answer ya question.
In any given stretch of four years, there are three normal years and one leap year. Therefore, 4 years is equal to (365 x 3) + 366 = 1461 days.
Since there are close to seven billion people living on Earth today, and there are only 365 days in a year (or 366 in a leap year) you can be sure that there are millions of people who have a birthday on any given day of the year.
Same as any other year (apart from leap) 365 days 52 weeks +1day.
Well, there's approximately 6.5 billion people in the world, and 365 days in the year. My calculator can't go up that high, but yes, it's generally a couple of million people's birthday on any given day. Well, there's approximately 6.5 billion people in the world, and 365 days in the year. My calculator can't go up that high, but yes, it's generally a couple of million people's birthday on any given day.
Given that any set of four years will contain one leap year, and one leap year only, the sum to work out will be:(3 x 365) + 366 + (15 x 7)This is equal to 1566 days.
No. Number of fortnights in a year = 365/14 = 26.07 (approx) which is fewer than the number of days in any month.
Short answer: 365 days in a year 365 days x 29 years = 10,585 days Long answer: 365 days a year There is a leap year every 4 years which has one less day. Accounting for subtracting one day every 4 years: 365 days x 29 years - (how many 4 year periods there are) (365 x 29) - (29/4) 10, 585 - 7.25 = 10,577.75 days (average accounting for leap years) If you want to know the exact number of days, you'll need to know the start or end year. This is because if the 29 year period starts on the year after a leap year, there will be one less leap year at the end. If the 29 year period starts on any other part of the 4 year cycle, there will be 1 more leap year than if it started on the year after a leap year.
Either 913 or 914 depending on whether one of the years is a leap year. ----------------------------------- If none of the years is a leap year: 1 year = 365 days → 2½ years = 2½ × 365 = 912½ days which could be rounded to 913 days if you count the half day as a whole day though it would then be a tad over 2½ years. If one of the years is a leap year, the extra day could be in one of the whole years: → 366 days + 1½ × 365 days = 913½ days which could be rounded to 914 days if you count the half day as a whole day, though it would then be a tad over 2½ years. If the last year, the half year, is a leap year: → 2 × 365 + ½ × 366 = 913 days. If we use a general year as 365¼ days: → 365¼ × 2½ = 913⅛ days → 2½ years is 912½, 913, 913⅛ or 913½ days depending upon which, if any of the years is a leap year, or a ¼ day is used for a general year. The best estimate for 2½ years is 913 days.
365 days in an ordinary year. Any 11-year span will include 2 or 3 leap years. You therefore add 2 or 3 days giving a grand total of 365*11 + 2 or 365*11 + 3 days. That is, 4017 or 4018 days. Divide by 7 to give 573.86 weeks or 574 weeks.
The song 365 Days wasn't released on any of the Victorious albums
ok let's try this! on any given date, probability that there is a student with a birthday is 30/365, so prob. that two students have that birthday is (30/365)^2. Tell me if I'm wrong, somebody! So the problem that this does NOT happen is 1-(30/365)^2 which is 0.9932445... I'm not sure about this next bit: there are 365 days in which this probably won't occur, does that make a difference?