Twelve. Here is how: Using cents rather than decimal dollars: 5n + 10d + 25q = 640 Express the numbers of nickels and quarters in terms of the number of dimes: # of nickels = twice the # of dimes ==> n = 2d # of quarters = 5 less than the # of dimes ==> q = d-5 Substitute for n & q in original equation: 5(2d) + 10d + 25(d-5) = 640 45d - 125 = 640 45d = 765 d = 17 ==> 170 = $1.70 n = 34 ==> 170 = $1.70 q = 12 ==> 300 = $3.00 . . . . . . . . . Total = $6.40
The coins in the store's cash register total $12.50. The cash register contains only nickels, dimes, and quarters. There are twice as many dimes as nickels. There are also twice as many quarters as dimes. How many quarters are in the cash register?
Peggy had three times as many quarters as nickels. She had $1.60 in all. How many nickels and how many quarters did she have?
Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?
7 quarters 2 dimes 4 nickels
You need to define variables for the different types of coins, write the corresponding equations, then solve them. One equation for each fact. Here are the equations:5N + 10D + 25Q = 1250 D = 2N Q = 2D
The question is incomplete. Please post a new version with the rest of the problem.
Nickles - 10 $0.50dimes - 20 $2.00quarters - 40 $10.000.50+2.00+10.00 = $12.50 containing 40 quarters---Here's how to solve this with Algebra :Let N be the number of nickels, so that2N is the number of dimes, and2(2N) or 4N is the number of quarters.A nickel is 5 cents, a dime is 10 cents, and a quarter is 25 cents,and the total in the cash register is $12.50Multiplying by their cents values, we have5(N) plus 10(2N) plus 25 (4N) = 12505N + 20N + 100N = 1250125 N = 1250N= 10So the number of nickels is 10, dimes 20, and quarters 40.
Each quarter is 25, and he has X quarters. Each dime is 10, and he has 2X dimes. Each nickel is 5. He has 12 coins in total, and all of the ones that are not quarters or dimes are nickels. Since quarters and dimes have to come in sets of 3, that's 12-3X. 25X + 10(2X) + 5(12-3X) = 120 25X + 20X - 15X + 60 =120 30X + 60 = 120 30X = 60 X = 2 He has 2 quarters, 4 dimes, and 6 nickels. To double check let's add them up: (2 * 25) + (4* 10) + (6 * 5) = 120
10 dimes 5 quarters
12 quarters 6 dimes
8 quarters and 16 nickels
There are fifteen (15) nickels.