[.3%] of [5L] = [0.3/100]*[5000 gram]= 15 g P.A.A
To calculate the amount of glucose in the solution, use the formula: mass = volume × concentration Rearrange the formula to solve for volume: volume = mass / concentration Substitute the values to find: volume = 75 g / 0.05 = 1500 mL = 1.5 L Therefore, you would need 1.5 liters of the 5.0% glucose solution to obtain 75 g of glucose.
The percent concentration of the codeine solution is 1.5%. This is calculated by dividing the mass of codeine (30g) by the total mass of the solution (2000g, since 1 liter of water is approximately 1000g) and then multiplying by 100.
33 percent of 2 gallons is equivalent to 0.66 gallon. When converted to liters, 0.66 gallon is approximately equal to 2.49 liters.
K2CrO4 Molarity (concentration) = moles of solute/Liters of solution (100 ml = 0.100 Liters ) Find moles K2CrO4 first. 3.50 grams = (1 mole K2CrO4/194.2 grams) = 0.01802 moles K2CrO4 ----------------------------------------------next Molarity = 0.01802 moles K2CrO4/0.100 Liters = 0.180 M K2CrO4 -------------------------
This is a calculation of the concentration of acetic acid (CH3COOH). To find the concentration, you divide the moles of CH3COOH by the volume of water in liters. So, the concentration would be 4.32 x 10^2 moles / 20.0 liters = 21.6 moles/liter.
Fifty percent of 3 liters is 1.5 liters. To calculate this, you simply multiply 3 liters by 0.50 (or 50%). Therefore, 50% of 3 liters equals 1.5 liters.
Well, isn't that a lovely little problem to solve? To decrease the concentration from 25% to 20%, we need to dilute the solution. Since the concentration is decreasing by 5%, we can calculate that we need to add 60 liters of water to the 300 liters of solution to achieve the desired concentration of 20%. Just like painting, a little change can make a big difference in creating the perfect mixture.
To calculate the molarity of a solution, you need to divide the moles of solute by the volume of the solution in liters. The formula for molarity is M moles of solute / liters of solution. This will give you the concentration of the solution in moles per liter.
To calculate moles from molarity, you use the formula: moles = molarity x volume (in liters). Simply multiply the molarity of the solution by the volume of the solution in liters to find the number of moles present in the solution.
Concentration of a solution is recorded in molarity (M). Molarity is the moles of solute divided my liters of solution. So to find the concentration of a solution, calculate the number of moles of the solute (the chemical being dissolved) and measure the number of liters of the solution (the water), then divide them.
There are 1950 liters of gasoline in the 650000 liters of water. This is calculated by multiplying the concentration of 3 ppm by the volume of water in liters.
The concentration of 58.5 g of NaCl in 2 L of solution is 29.25 g/L. To calculate the concentration, divide the mass of the solute (NaCl) by the volume of the solution (in liters).
0.5 percent of 75 liters is 0.375l.
To find the molarity of a solution with a percent concentration of a solute, you need to know the molecular weight of the solute and the density of the solution. Then, you can use the formula: Molarity (percent concentration density) / (molecular weight 100).
To prepare 6 nM ammonium hydroxide a 30 percent solution you need to know the volume of the 30 percent solution that you have and the volume of 6nM solution you would like to make. Then use the following formula: C1V1 = C2V2 where C = concentration in moles/Liter and V = volume in liters.
200 milliliters
To calculate the amount of glucose in the solution, use the formula: mass = volume × concentration Rearrange the formula to solve for volume: volume = mass / concentration Substitute the values to find: volume = 75 g / 0.05 = 1500 mL = 1.5 L Therefore, you would need 1.5 liters of the 5.0% glucose solution to obtain 75 g of glucose.