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What is the molarity of a 5.00x 10 2ml solution containing 249g of k?
Molarity = moles of solute/Liters of solution some conversion needed 5.00 X 102 ml = 0.5 liters ------------------------------------- 249 grams K (1 mole K/39.10 grams = 6.37 moles potassium ------------------------------------------------------------------------------- Molarity = 6.37 mole K/0.5 Liters = 12.7 M K -----------------( as expected, highly concentrated solution )
If a chemistry student collected 834 mL of gas at 25ºC and 8.00 102 torr how many moles did she collect?
0.0359
If a chemistry student collected 834 mL of gas at 25ºC and 8.00 × 102 torr, how many moles did she collect?
0.0359
Is there 143g mol in 6.80g of al2o3?
To determine if there are 143 g/mol in 6.80 g of Al₂O₃, we first need to calculate the molar mass of Al₂O₃. The molar mass of Al₂O₃ is approximately 102 g/mol (with aluminum at about 27 g/mol and oxygen at about 16 g/mol). To find the number of moles in 6.80 g of Al₂O₃, we divide the mass by the molar mass: 6.80 g ÷ 102 g/mol ≈ 0.067 moles. Thus, there are no 143 g/mol in 6.80 g of Al₂O₃; the molar mass is actually around 102 g/mol.
Calculate the mass of ki in grams required to prepare 5.00 102 ml of a 2.80 m solution?
To calculate the mass of KI needed for a 2.80 m solution, we first need to know the molality (m) and the volume of the solution. The molality is defined as moles of solute per kilogram of solvent. For a 2.80 m solution, we have 2.80 moles of KI per kg of solvent. Given the volume of 5.00 x 10² mL (or 0.500 kg of water, assuming the density of water is 1 g/mL), we can use the formula: Mass of KI = moles of KI × molar mass of KI. Calculating, we find that 2.80 moles of KI correspond to about 2.80 × 166 g/mol (molar mass of KI) = 464.8 g of KI. Thus, you need approximately 464.8 grams of KI.
How many gallons are in 102 Liters?
102 liters (L) = 26.94554934 gallons (gal) [US liquid]
What is the molarity of a 2.50 x 102 cm3 solution containing 45.0 g of C6H12O6?
Molarity is defined as moles solute/liter of solution.Moles of solute = 2.5 moles sucrose Liters of solution = 0.5 liters Molarity (M) = 2.5 moles/0.5 liters = 5 M
What is the molarity of a 5.00x 10 2ml solution containing 249g of k?
Molarity = moles of solute/Liters of solution some conversion needed 5.00 X 102 ml = 0.5 liters ------------------------------------- 249 grams K (1 mole K/39.10 grams = 6.37 moles potassium ------------------------------------------------------------------------------- Molarity = 6.37 mole K/0.5 Liters = 12.7 M K -----------------( as expected, highly concentrated solution )
How do you calculate the volume in milliliters of a 0.61M sodium nitrate solution that contains 400mmol of sodium nitrate?
By definition, a 0.61M sodium nitrate solution contains 0.61 moles of sodium nitrate per liter, which is equivalent to 0.61 mmol/ml. Therefore, the volume of this solution required to contain 400mmol is 400/0.61 or 6.6 X 102 ml, to the justified number of significant digits.
Fuel Capacity of Dodge Durango 2006?
27 U.S. Gallons (102 Liters)
How many liters are in 4.50 moles of chlorine gas?
Since you don't specify the conditions, I will use the current STP. At STP of 0oC (273.15 K for gases) and 100 kPa, the molar volume of a gas is 22.711 L/mol.4.50 mol Cl2 x 22.711 L/mol = 102 L Cl2, rounded to three significant figures.Just in case your teacher is using the older version of STP of 0oC (273.15 K for gases), and 1 atm, the molar volume of a gas would be 22.414 L/mol.4.50 mol Cl2 x 22.414 L/mol = 101 L Cl2, rounded to three significant figures.
How much oil do you put in the gas for a 2002 rm 125 2-stroke?
102 liters
What is 10 percent of 6 liters?
102% of 6 litres = 6*10/100 = 0.6 litres.
How many moles are in 6.80 g of Al2O3?
Remember the Moles Eq'n. moles = mass(g) / Mr The Mr ( Relative molecular mass of Al2O3) is . 2 x Al = 2 x 27 = 54 3 x O = 3 x 16 = 48 54 + 48 = 102 substituting moles(Al2O3) = 6.8 g / 102 moles = 0.0666.... ( recurs to infinity.
If a chemistry student collected 856 mL of gas at 25C and 7.40 102 torr how many moles did she collect?
0.0341
If a chemistry student collected 834 mL of gas at 25ºC and 8.00 102 torr how many moles did she collect?
0.0359
If a chemistry student collected 834 mL of gas at 25ºC and 8.00 × 102 torr, how many moles did she collect?
0.0359
