Since you don't specify the conditions, I will use the current STP. At STP of 0oC (273.15 K for gases) and 100 kPa, the molar volume of a gas is 22.711 L/mol.
4.50 mol Cl2 x 22.711 L/mol = 102 L Cl2, rounded to three significant figures.
Just in case your teacher is using the older version of STP of 0oC (273.15 K for gases), and 1 atm, the molar volume of a gas would be 22.414 L/mol.
4.50 mol Cl2 x 22.414 L/mol = 101 L Cl2, rounded to three significant figures.
0.1125
1 mol of H2 is necessary.
Molarity = moles of solute/Liters of solution get moles KOH 6.31 grams KOH (1 mole KOH/56.108 grams) = 0.11246 moles KOH 0.250 M KOH = 0.11246 moles KOH/XL 0.11246/0.250 = 0.4498 liters = 450 milliliters
Molarity = moles/litermoles = 9.33 g Na2S x 1 mole/78 g = 0.1196 molesliters = 450 ml x 1L/1000 ml = 0.45 Lmolarity = 0.1196 moles/0.45 L = 0.266 M = 0.27 M (2 sig figs)
For this you need the atomic (molecular) mass of HNO3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. HNO3= 63.0 grams2.00 moles HNO3 × (63.0 grams) = 126 grams HNO3
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters) 5M C6H12O6 = moles C6H12O6/0.450 liters = 2.25 moles C6H12O6 (180.156 grams/1 mole C6H12O6) = 405.351 grams of glucose ( you do significant figures )
A 450-ml volume of alcohol is how many liters?
450 moles of C2H4 contain 10.815,43 g carbon.
450 liters = 118.877 gallons or 15,216.3 oz
450 mL = 0.45 L
0.45l
450 liters is 15,216.3 fluid ounces.
There are 4500 centiliters in 45 liters.
0.45 litres
450
450 ml