Since you don't specify the conditions, I will use the current STP. At STP of 0oC (273.15 K for gases) and 100 kPa, the molar volume of a gas is 22.711 L/mol.
4.50 mol Cl2 x 22.711 L/mol = 102 L Cl2, rounded to three significant figures.
Just in case your teacher is using the older version of STP of 0oC (273.15 K for gases), and 1 atm, the molar volume of a gas would be 22.414 L/mol.
4.50 mol Cl2 x 22.414 L/mol = 101 L Cl2, rounded to three significant figures.
To find the number of moles of hydrogen gas, we first need to calculate the number of moles of chlorine gas using the ideal gas law formula (PV = nRT). Once we have the moles of chlorine gas, we can determine the moles of hydrogen gas needed for the reaction. In this case, the stoichiometry of the reaction states that 1 mole of chlorine gas reacts with 1 mole of hydrogen gas, so the required moles of hydrogen gas will be equal to the moles of chlorine gas.
First, calculate the number of moles of NaOH: Moles = Molarity x Volume (L) Convert mL to L: 450 mL = 0.45 L Moles = 0.25 N x 0.45 L = 0.1125 moles of NaOH.
To calculate the molarity, you first need to convert the grams of NaOH to moles using the molar mass of NaOH (40 g/mol). Then, you divide the moles of NaOH by the volume of solution in liters (450 ml = 0.45 L) to get the molarity. Molarity = moles of NaOH / volume of solution in liters Moles of NaOH = 95 g / 40 g/mol = 2.375 mol Molarity = 2.375 mol / 0.45 L = 5.28 M
Molarity = moles/litermoles = 9.33 g Na2S x 1 mole/78 g = 0.1196 molesliters = 450 ml x 1L/1000 ml = 0.45 Lmolarity = 0.1196 moles/0.45 L = 0.266 M = 0.27 M (2 sig figs)
Molarity = moles of solute/Liters of solution get moles KOH 6.31 grams KOH (1 mole KOH/56.108 grams) = 0.11246 moles KOH 0.250 M KOH = 0.11246 moles KOH/XL 0.11246/0.250 = 0.4498 liters = 450 milliliters
Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters) 5M C6H12O6 = moles C6H12O6/0.450 liters = 2.25 moles C6H12O6 (180.156 grams/1 mole C6H12O6) = 405.351 grams of glucose ( you do significant figures )
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
450 moles of C2H4 contain 10.815,43 g carbon.
450 liters = 118.877 gallons or 15,216.3 oz
A 450-ml volume of alcohol is how many liters?
450 mL = 0.45 L
There are 0.45 liters in 450 ml volume of alcohol.
There are 100 centilitres in one litre. Therefore, 450 centilitres is equal to 450/100 = 4.5 litres.
0.45l
To find the number of moles of hydrogen gas, we first need to calculate the number of moles of chlorine gas using the ideal gas law formula (PV = nRT). Once we have the moles of chlorine gas, we can determine the moles of hydrogen gas needed for the reaction. In this case, the stoichiometry of the reaction states that 1 mole of chlorine gas reacts with 1 mole of hydrogen gas, so the required moles of hydrogen gas will be equal to the moles of chlorine gas.
450 liters is 15,216.3 fluid ounces.
There are 4500 centiliters in 45 liters.