Molarity = moles/liter
moles = 9.33 g Na2S x 1 mole/78 g = 0.1196 moles
liters = 450 ml x 1L/1000 ml = 0.45 L
molarity = 0.1196 moles/0.45 L = 0.266 M = 0.27 M (2 sig figs)
total gram of KH2AsO4 = 180.033 1gram of As = 33 Arsenic ratio in KH2AsO4; 180.033/33= 5.45 gram However, 5.45 gram of KH2AsO4 add to volumetric flask and exactly dilute with 1000 ml pure water.
To determine the concentration of the solution, we need to calculate the total mass of the solution first. The total mass is the sum of the mass of sugar (25 g) and the mass of water (50 g), which equals 75 g. The concentration of the solution is then calculated by dividing the mass of the solute (sugar) by the total mass of the solution: (25 g / 75 g) x 100% = 33.33%. Therefore, the concentration of the solution is 33.33%.
There are 33 electrons in an Arsenic atom.
bp= 100.33 degrees Celsius (10.5 ATM= m x .0821 x198.15) (m= .645mol) (Change of Tb= .512 degree Celsius/mol x .645mol) (Change of Tb= .33 degrees Celsius) (.33 + 100= 100.33)
Let us assume that x pint water must be mixed with 4 pints of 50 percent acetic acid to produce a mixture that is 33 percent acetic acid. Therefor 4 pint*50 %=(4+x)pint*33% 200 =132 pints + x pints 200-132 = x*33 pints 68 /33 = x pints So x = 2.06 pints Answer : 2.06 pint water must be mixed with 4 pints of 50 percent acetic acid to produce a mixture that is 33 percent acetic acid.
(33 and 1/3) percent
Solve the inequality and enter your solution as an inequality comparing the variable to the solution. -33+x<-33
To find the molarity, we first need to convert the mass of water to moles. Since 1 kg of water is approximately 1000 moles, 3 kg of water is 3000 moles. Then, molarity is calculated by dividing the number of moles of solute (NaOH) by the volume of solution in liters. So, the molarity would be 6 moles / 3 L = 2 M.
% rate = 33/31 * 100% = 106.45%
The Honda 450 R came from the factory with 33 hp
33
A solution to the four fours problem for the number 33 is: 33 = (4-.4)/.4+4!
145.45%Solution:33 * x/100% = 48x = (48/33)*100%x = 1.4545 * 100%x = 145.45%
5w+3 = 33 5w = 30 w = 6
81.818% Solution: 81818 = 1-(6/33)
so it is 33% already. You need to dilute every 33ml with 30.5ml solvent and adding 2.5ml of the solution. Feel free to message if you need further explaining
The only integer solution to this is 33.