450 moles of C2H4 contain 10.815,43 g carbon.
85.636 grams carbon (1 mole C/12.01 grams) = 7.1304 moles of carbon ---------------------------------
0,666 moles
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
Balanced equation C2H4 + 3O2 -> 2CO2 + 2H2O 125 grams ethylene (1 mole C2H4/28.052 grams)(2 mole CO2/1 mole C2H4)(44.01 grams/1 moleCO2) = 392 grams CO2 formed ==================
Diamonds are all carbon. just divide 1200 grams by 12.01 grams per mole carbon.
85.636 grams carbon (1 mole C/12.01 grams) = 7.1304 moles of carbon ---------------------------------
To calculate the number of moles of carbon dioxide in 19 grams, divide the given mass by the molar mass of carbon dioxide, which is approximately 44 grams/mol. Therefore, 19 grams of carbon dioxide is equal to 19/44 ≈ 0.43 moles.
About one half mole. 6 grams carbon (1 mole C/12.01 grams) = 0.4996 moles of carbon --------------------------------- that is, 0.5 moles carbon ---------------------------------
0,666 moles
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
Balanced equation C2H4 + 3O2 -> 2CO2 + 2H2O 125 grams ethylene (1 mole C2H4/28.052 grams)(2 mole CO2/1 mole C2H4)(44.01 grams/1 moleCO2) = 392 grams CO2 formed ==================
1 gram carbon (1 mole C/12.01 grams) = 0.08 moles carbon ===============
30.0 grams carbon (1 mole C/12.01 grams) = 2.50 moles carbon ===============
The balanced reaction for converting 1 mol of C2H4 to C2H4F2 using F2 gas is: C2H4 + 2 F2 -> C2H4F2 First, calculate the moles of C2H4 in 100g. Then, using the mole ratio from the balanced equation, determine how many moles of F2 are needed. Finally, convert the moles of F2 to liters using the ideal gas law (PV = nRT) at the given conditions.
One Mole of C2H4 will containt 6.0221415×10^23 molecules of C2H4. Therefore 2.23 Moles of C2H4 will contain 1.39713683x10^24 molecules of C2H4. There are 4 Hydrogen atoms in C2H4, so 1.39713683x10^24 x 4 = 5.58854732X10^25 atoms of hydrogen.
The formula for Ethylene_ C2H4 STEP 1 Calculate the RMM (Relative molecular mass) of C2H4 C-carbon= 12; H-hydrogen= 1 (check your periodic table people!!!) C*2 + H*4 = 12*2 + 1*4 = 24 + 2 =28 amu/g So... one mole of ethylene has a mass of 28 grams. Number of Moles= Mass / mass of 1 mole ("/" to divide) The mass given is 122g 122g/28g = 4.36 moles Approx 4.4 moles
Look up the molecular weight of carbon dioxide in the periodic table. The formula for carbon dioxide is CO2, which means one atom of carbon and two atoms or oxygen per molecule of carbon dioxide. Carbon has molecular weight of 12. Oxygen molecular weight is 16. Total 12+16+16= 44 11 grams/44 grams/mole=0.25 moles of carbon The grams of water and combustion of 7.5 grams are totally irrelevant. They are only given to possibly confuse you.