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Remember the Moles Eq'n.
moles = mass(g) / Mr
The Mr ( Relative molecular mass of Al2O3) is .
2 x Al = 2 x 27 = 54
3 x O = 3 x 16 = 48
54 + 48 = 102
substituting
moles(Al2O3) = 6.8 g / 102
moles = 0.0666.... ( recurs to infinity.
What else can I help you with?
Calculate the number of moles in 6.80g of Al2O3?
To calculate the number of moles in a sample of Al2O3, we need to use the molar mass of Al2O3, which is 101.96 g/mol. Number of moles = Mass / Molar mass = 6.80g / 101.96 g/mol ≈ 0.067 moles. Therefore, there are approximately 0.067 moles of Al2O3 in 6.80g of the compound.
What is the number of mole in 50.0g of aluminum oxide?
To find the number of moles in 50.0g of aluminum oxide, you first need to determine the molar mass of Al2O3, which is 101.96 g/mol. Then, you divide the given mass by the molar mass to get the number of moles: 50.0g / 101.96 g/mol = 0.490 moles.
How many aluminum atoms are in 291.257 grams of Al2O3?
The gram molecular mass of Al2O3 is 2(26.982) + 3 (15.999) = 101.96. Therefore, the number of moles of Al2O3 is 291.257/101.96 = 2.857 moles. Each mole contains two moles of aluminum atoms; therefore the number of aluminum atoms in this mass equals 2 X 2.857 X 6.022 X 1023 = 3.4410 X 1024 atoms.
What is the percentage of aluminum in aluminum oxide (Al2O3)?
The formula for aluminum oxide is Al2O3: Molar mass =581.77g/mol Al2O3.In one mole Al2O3, there are two moles of Al3+ ions, therefore 2 moles Al3+ x 26.982g/mol Al3+ = 53.964g Al3+ in one mole of Al2O3.GIVEN: mass of Al3+ = 53.964 g Al3+;Molar mass of Al2O3 = 581.77 g Al2O3UNKNOWN: % Al3+EQUATION:% Al3+...=...g Al3+x 100...g Al2O3% Al3+...=...53.964g Al3+x100......=...9.2758% Al3+581.77g Al2O3
How many moles of aluminum oxide are present in a sample having a mass of 178.43g?
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
How many moles of Al2O3 are present in 49.3 g of this compound?
To find the number of moles, we need to use the molar mass of Al2O3, which is 101.96 g/mol. Divide the given mass (49.3 g) by the molar mass to get the number of moles of Al2O3 present. 49.3 g / 101.96 g/mol ≈ 0.483 moles of Al2O3.
Calculate the number of moles in 6.80g of Al2O3?
To calculate the number of moles in a sample of Al2O3, we need to use the molar mass of Al2O3, which is 101.96 g/mol. Number of moles = Mass / Molar mass = 6.80g / 101.96 g/mol ≈ 0.067 moles. Therefore, there are approximately 0.067 moles of Al2O3 in 6.80g of the compound.
What is the mass in grams of 9.27 moles of Al2O3?
The molar mass of Al2O3 is 101.96 g/mol. To calculate the mass of 9.27 moles of Al2O3, you would multiply the moles by the molar mass: 9.27 mol x 101.96 g/mol = 945.442 g. So, the mass of 9.27 moles of Al2O3 is approximately 945.442 grams.
What is the mass in grams of 2.38 moles of Al2O3?
The answer is 242,6648 g.
What is the percent yield of this reaction if 750.0 g of aluminum oxide produced 256.734 g of aluminum?
Aluminum oxide, Al2O3 would produce aluminum by the following decomposition:2Al2O3 ==> 4Al + 3O2 750.0 g Al2O3 x 1 mole/101.96 g = 7.356 moles Al2O3 Theoretical yield of Al = 7.356 moles Al2O3 x 4 moles Al/2 mole Al2O3 = 14.71 moles Al Theoretical mass of Al = 14.71 moles Al x 26.98 g/mole = 396.9 g Al Percent yield = 256.734 g/396.9 g (x100%) = 64.68% yield (to 4 significant figures)
What is the number of mole in 50.0g of aluminum oxide?
To find the number of moles in 50.0g of aluminum oxide, you first need to determine the molar mass of Al2O3, which is 101.96 g/mol. Then, you divide the given mass by the molar mass to get the number of moles: 50.0g / 101.96 g/mol = 0.490 moles.
How many grams of oxygen are in 5.75 moles of aluminum oxide?
Well to find how many grams are in moles you would eventually multiply the mole by the molar mass. The molar mass of aluminum oxide would be 101.96 ( you would find that by multiplying the atomic mass of al by 2 and o by 3 and adding them together). But the molar mass of Oxygen is just about 48 (rounded to 16 instead of 15.9994)5.75 moles of Al2O3 X 48 g oxygen/1 mole of Al2O3=276 g oxygen in 5.75 mole Al2O3
Calculate the number of grams of Al in 371 g of Al2O3?
To calculate the number of grams of Al in 371 g of Al2O3, you first need to determine the molar mass of Al2O3 (102 g/mol). Then, calculate the molar mass of Al (27 g/mol). From the chemical formula Al2O3, you can see that there are 2 moles of Al for every 1 mole of Al2O3. Therefore, by using these ratios, you can determine that there are 162 g of Al in 371 g of Al2O3.
What is the molarity of a solution in which 51 grams of aluminum oxide Al2O3 is dissolved in 500 mL of solution?
Need moles aluminum oxide first. 51 grams Al2O3 (1 mole Al2O3/101.96 grams) = 0.5002 moles Al2O3 ======================Now, Molarity = moles of solute/Liters of solution (500 ml = 0.500 Liters ) Molarity =0.5002 moles Al2O3/0.500 Liters = 1.0 M Al2O3 solution ----------------------------
Calculate the mass of alumina produced from two moles of the ore?
The concentration of alumina in the ore is necessary; also the effective yield.
How many aluminum atoms are in 291.257 grams of Al2O3?
The gram molecular mass of Al2O3 is 2(26.982) + 3 (15.999) = 101.96. Therefore, the number of moles of Al2O3 is 291.257/101.96 = 2.857 moles. Each mole contains two moles of aluminum atoms; therefore the number of aluminum atoms in this mass equals 2 X 2.857 X 6.022 X 1023 = 3.4410 X 1024 atoms.
What is the percentage of aluminum in aluminum oxide (Al2O3)?
The formula for aluminum oxide is Al2O3: Molar mass =581.77g/mol Al2O3.In one mole Al2O3, there are two moles of Al3+ ions, therefore 2 moles Al3+ x 26.982g/mol Al3+ = 53.964g Al3+ in one mole of Al2O3.GIVEN: mass of Al3+ = 53.964 g Al3+;Molar mass of Al2O3 = 581.77 g Al2O3UNKNOWN: % Al3+EQUATION:% Al3+...=...g Al3+x 100...g Al2O3% Al3+...=...53.964g Al3+x100......=...9.2758% Al3+581.77g Al2O3
