What is the percentage of aluminum in aluminum oxide (Al2O3)?

Answer 1

The formula for aluminum oxide is Al2O3: Molar mass =581.77g/mol Al2O3.

In one mole Al2O3, there are two moles of Al3+ ions, therefore 2 moles Al3+ x 26.982g/mol Al3+ = 53.964g Al3+ in one mole of Al2O3.

GIVEN: mass of Al3+ = 53.964 g Al3+;Molar mass of Al2O3 = 581.77 g Al2O3

UNKNOWN: % Al3+

EQUATION:

% Al3+...=...g Al3+x 100...g Al2O3

% Al3+...=...53.964g Al3+x100......=...9.2758% Al3+581.77g Al2O3

Answer 2

Aluminum oxide (Al2O3) is composed of two aluminum atoms and three oxygen atoms. The molar mass of aluminum is 26.98 g/mol, and the molar mass of oxygen is 16.00 g/mol. Therefore, the percentage of aluminum in aluminum oxide is calculated as (2*26.98 g / 101.96 g) * 100%, which is approximately 52.9%.

Answer 3

The percentage of aluminium in aluminium oxide is 52,94.