Total number of different ways he can fill out the answer sheet = 210 = 1,024 .
He passes the test if he gets zero wrong, one wrong, or two wrong.
Number of ways to get zero wrong = 1.
Number of ways to get exactly one wrong = 10.
Number of ways to get exactly two wrong = 45.
Total number of ways to get exactly 0, 1, or 2 wrong = (1 + 10 + 45) = 56.
Probability of passing = (56) / (1,024) = 5.47%(rounded)
2
16.7%
If there are four possible answers to a question, then a guessed answer would have a probability of 1 in 4. If there are six questions, then the mean number of correct answers would be six times 1 in 4, or 1.5
3/40 = 0,075 0,075 x 100 = 7,5 % 100% - 7,5 % = 92,5 % correct
which two of these three events are complementary? a. The probablity that a student makes more than 13 mistakes is .32 B. The probability that a student makes 3 or more mistakes is .56 C. The probability that a student makes at most 13 mistakes is .68
45/1024 = 4.4%, approx.
0.05 I think is the answer
What is the probability of what?Guessing them all correctly?Getting half of the correct?Getting them all wrong?PLEASE be specific with your questions if you want WikiAnswers to help.
7/128, or about 5.5% The student has a 1/2 probability of getting each question correct. The probability that he passes is the probability that he gets 10 correct+probability that he gets 9 correct+probability that he gets 8 correct: P(passes)=P(10 right)+P(9 right)+P(8 right)=[(1/2)^10]+[(1/2)^10]*10+[(1/2)^10]*Combinations(10,2)=[(1/2)^10](1+10+45)=56/1024=7/128.
2
16.7%
Assuming the questions are answered at random, the probability is 0.000009, approx.
This is abinomial distribution; number of trials (n) is 5, probability of success (p) is 1/4 or 0.25. With this information you can go to a Binomial Distribution Table and find the solution. Within the section of values for n=5 and p=.25, read from the section the probability of 4 which is 0.0146 (see related link for table).
If there are four possible answers to a question, then a guessed answer would have a probability of 1 in 4. If there are six questions, then the mean number of correct answers would be six times 1 in 4, or 1.5
Hello
The percent that 35 is increased from 25 is (35 - 25) / 25 * 100, or 40 percent.
The probability is indeterminate. I might ask a student or I might not.