Decrease by a factor of 9
Light intensity is inversely proportional to the square of the distance: I = k/d2
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
No, it follows the inverse square law. That is, the intensity is inversely proportional to the square of the distance. I2/I1 = (r1/r2)². Intensity decreases with 1/r² from increased distance, while the sound pressure decreases only with 1/r from increased distance.
Because the constant amount of light that the flashlight produces is spread out over a larger area when it's farther away, so the intensity at every point is less. Light decreases inversely to the square of the distance.
The intensity reduces in proportion to the square of your distance from the source.
Become one ninth.
If n is the intensity of light whose path is perpendicular to a surface (parallel to the normal), the intensity of the same light from the same distance onto the same surface but with an angle of incidence (measured from the normal) of Θ is n cosΘ (n times the cosine of theta).
Light intensity is inversely proportional to the square of the distance: I = k/d2
The illumination on the surface would be reduced by a factor of four, thereforeif the distance from a light source is doubled, the illumination provided by the source is one fourth as great.
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
- 6 dB is incorrect. It will decrease by 12 dB.
No, it follows the inverse square law. That is, the intensity is inversely proportional to the square of the distance. I2/I1 = (r1/r2)². Intensity decreases with 1/r² from increased distance, while the sound pressure decreases only with 1/r from increased distance.
No but parallel lines have a constant distance between them
The Conservation of Energy or power Law. This gives the inverse distance law of Intensity: Intensity on Earth = intensity on sun (radius/sun distance to earth)2 .
Because the constant amount of light that the flashlight produces is spread out over a larger area when it's farther away, so the intensity at every point is less. Light decreases inversely to the square of the distance.
The intensity reduces in proportion to the square of your distance from the source.
Its loudness at a particular distance