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one car is traveling at 55 kilometers per hour the other is at 70
let x = speed of first car
=> speed of second car = x+15
knowing that the total milage covered in 4 hours was 500 Km
x+(x+15) = 500/4
2x + 15 = 125
2x = 110
x = 55
=> car one is 55 Kph
=> car two is 70 Kph
to check work, in 4 hours, car one travels 55 * 4 Km => 220 Km
car two travels 70 * 4 Km => 280 Km
220 + 280 = 500 Km
What else can I help you with?
What is the frame of reference for a plane moving at 500kmh?
The frame of reference for a plane moving at 500 km/h is typically Earth's surface. This is because the speed of the plane is measured relative to the ground, which is considered at rest in this context.
What is the frame reference for a plane moving at 500kmh?
The frame of reference for a plane moving at 500 km/h can be either the ground or the surrounding air. In both cases, the speed of the plane relative to these frames of reference would be 500 km/h.
If an aircraft flew at 400km an hour to its destination and returned at 500kmh and the total trip equals 9 hours how far did the aircraft fly and how do you do the formula to solve?
NRP (no-return point) = Range(in hours) x V(out) x V(in) / V(out) + V(in) = 2000km
