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Two forces of 10N and 16N act at 60degrees to each other What is the magnitude and direction of the force needed to balance them?
Wiki User
∙ 14y ago
Let's say the direction of the 10 N force is 0 degrees. The 16 N force has a component of 16 N cos(60°) in the direction of the 10 N force and a component of 16 N sin(60°) in the perpendicular 90° direction. Adding the two gives a √( ((16 cos(60°)+10)2 + (16 sin(60°))2 ) ≅ 22.7 N force in the atan( 16 sin(60°) / (16 cos(60°)+10) ) ≅ 37.6° direction.
Counteracting this would require a force of 22.7 N in the 37.6°+180° = 217.6° direction.
Wiki User
∙ 14y ago
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