200.106m2
Area = 0.5*(sum of parallel sides)*height There also is a little rhyme to help you remember that i leanreed in year 7: half the sum of the parallel sides times the distance between them thats the way that i found out the area of a trapezium; sung in the way of the pied piper song.
Here is one way. Find the average of the two parrallel sides (i.e. the top and bottom), and then multiply that by the height. That's it. To find the average of the parrallel sides, add them to gether and divide by two. Example: average of 4 and 6 = (4+6) divided by 2. Which equals 10 divided by 2 which is 5. That's it. And 5 looks right to because its in between 4 and 6.
The area is 12889 sq metres, approx.
Area = 16.2 sq metres.
Suppose the sides are a, b and c with c being the hypotenuse. Then 1/2*a*b is the area which is known. Therefore b = 2*area/a Also, by Pythagoras, c = sqrt(a2 + b2) so that, using the previous result, c can be expressed in terms of a. So, you now have a + b + c = perimeter where both b and c can be expressed in terms of a. This gives a quadratic equation that can be solved for a. The two solutions are a and b, since flipping the triangle will swap the base and height.
Let the two parallel sides be a and b, and the distance between them, the height of the trapezium, be h. Then: area of trapezium = 1/2 (a+b) h That is half the sum of the two parallel sides times the height of the trapezium.
Area = 0.5*(sum of parallel sides)*heightNote: A trapezium in the UK is known as a trapezoid in the USA
The area of a trapezium is found because: 0.5*(sum of parallel sides)*height = area
If the two parallel side of the trapezium are a and b and height of the trapezium (the distance between the parallel sides) is h then the area is given by:Area = 1/2 (a + b) x hHalf the sum of the lengths of the parallel sides times the distance between them.
Area = 0.5*(sum of parallel sides)*heightNote: A trapezium in the UK is known as a trapezoid in the USA
Area of a trapezium = 0.5*(sum of parallel sides)*height
Area = 1/2*(sum of the parallel sides)*height
has two parallel sideshas four straight linesThe area of the trapezium is given by the following formula where a and b are the lengths of the parallel sides and h is the perpendicular distance between the parallel sides.
A trapezium has a pair of parallel sides of different lengths so in order to find its 2nd parallel side the information given must include its height.
Suppose you have a trapezium whose parallel sides (bases) are of lengths A and B units, and where the height is h units If you flip a trapezium over and append it to the original along one of the bases you will have a parallelogram whose base is A+B units in length and whose height is h units. So 2*Area of trapezium = Area of parallelogram = (A + B)*h
Suppose the base and parallel sides of the trapezium are labelled a and b. Suppose, also, that the distance between a and b is h. Draw a diagonal. This will split the trapezium into one triangle whose base is the trapezium's base (a) and another upside-down triangle whose base is the trapezium's top (b). The heights of both these triangles will be the same as the distance between the parallel sides of the trapezium (h). The area of the first triangle is 0.5*a*h The area of the second triangle is 0.5*b*h So the area of the trapezium = 0.5*a*h + 0.5*b*h = 0.5*(a+b)*h
It is: 0.5*(sum of its parallel sides)*height