1:2
I guess you mean the ratio of the areas; it depends if the 2 rectangles are "similar figures"; that is their matching sides are in the same ratio. If they are similar then the ratio of their areas is the square of the ratio of the sides.
area of triangle 1 would be 16 and the other triangle is 9 as the ratio of areas of triangles is the square of their similar sides
False: Ratio areas= 16 : 64 = 1 : 4 Ratio of sides = sqrt(ratio of areas) = 1 : 2
The corresponding sides of similar solids have a constant ratio.
It is given that two triangles are similar. So that the ratio of their corresponding sides are equal. If you draw altitudes from the same vertex to both triangles, then they would divide the original triangles into two triangles which are similar to the originals and to each other. So the altitudes, as sides of the similar triangles, will have the same ratio as any pair of corresponding sides of the original triangles.
I guess you mean the ratio of the areas; it depends if the 2 rectangles are "similar figures"; that is their matching sides are in the same ratio. If they are similar then the ratio of their areas is the square of the ratio of the sides.
area of triangle 1 would be 16 and the other triangle is 9 as the ratio of areas of triangles is the square of their similar sides
False: Ratio areas= 16 : 64 = 1 : 4 Ratio of sides = sqrt(ratio of areas) = 1 : 2
ratio of areas = (ratio of sides)² ratio of sides = 3 : 5 → ratio of areas = 3³ : 5² = 9 : 25 → area larger = 81 m² ÷ 9 × 25 = 225 m²
Yes, all squares are similar because they are all in proportion. The angles will always be 90 degrees, and the sides proportionate. The same ratio can be created using any two side measures between squares. Thus, all squares are similar.
Assume square A with side a; square B with side b. Perimeter of A is 4a; area of A is a2. Perimeter of B is 4b; area of B is b2. Given the ratio of the perimeters equals the ratio of the areas, then 4a/4b = a2/b2; a/b = a2/b2 By cross-multiplication we get: ab2 = a2b Dividing both sides by ab we get: b = a This tells us that squares whose ratio of their perimeters equals the ratio of their areas have equal-length sides. (Side a of Square A = side b of Square B.) This appears to show, if not prove, that there are not two different-size squares meeting the condition.
The ratio of volumes is directly proportional to the cube of the ratio of their sides. And, incidentally, all cubes are similar.
Areas are proportional to the square of corresponding sides. Therefore, in this case: * Divide 144 by 36. * Take the square root of the result. That will give you the ratio of the corresponding sides.
The corresponding sides of similar solids have a constant ratio.
Congruent figures are similar - in sides as well as angles. Corresonding angles of similar figures congruent but their sides are not. The sides are all in some fixed ratio. [If that ratio is 1, the figures are congruent.]
16/25
Only if they both have the same ratio of length to width. Since every square has the same ratio of length to width ( it's 1 ), all squares are similar. Gee, when you think about it, every regular polygon is similar to every other regular polygon with the same number of sides. I never realized that.