-b +/- sqrt(b^2 - 4ac)/2a
a = 1
b = -7
c = -18
7 +/- sqrt( 49 + 72 )/2
7 +/- 11/2
roots are; 9 and -2 ( my TI-84 confirms this answer )
This kind of question usually accompanies a specific table of ordered pairs. The idea is that the ordered pairs take the form of (x, f(x)) where the first number of the ordered pair x, is a value of the variable for some equation. When that value is used in place of the variable in the equation, we can calculate a specific value. That calculated value appears as the second value of the ordered pair and is represented by f(x) above. Typically the equation is relatively simple, such as a linear equation or a quadratic equation. Therefore, in order to determine the equation, we have to know exactly what the ordered pairs are.
There is not "the ordered pair" but infinitely many ordered pairs which, taken together, comprise the straight line defined by the equation.
There is not "the ordered pair" but infinitely many ordered pairs which, taken together, comprise the straight line defined by the equation.
an ordered pair
An ordered pair is a solution only of a linear equation in two variables - not any linear equation. Often the variables are denoted by x and y. If the first of the ordered pair is substituted for x in the equation, and the second for y, then the equation represents a true statement.
Graph of an equation.
13
I am sorry but the question is incomplete. You have not mentioned the ordered pairs and the equation is incomplete as well.
15
Select any three values of x in the domain of the equation. Solve the equation at these three points for the other variable, y. Then each (x, y) will be an ordered pair that is a solution of the equation.
The question cannot be answered unless a specific equation is cited.
There are infinitely many ordered pairs: each point on the straight line defined by the equation is an ordered pair that is a solution. One example is (0.5, 2.5)