NONE! The 80186 was an advanced version of the 8086 but did not include support for virtual memory. It had a 64K physical address space. The 80286 was the first Intel CPU to support virtual memory but it's capabilities were limited.
The Intel 80386 can address 4 GB of physical memory and 64 TB of virtual memory.
4 GB
Max length of memory segment =4GB there r 8KB number of descriptor in GDT and 8KB in LDT . So total numbr of descriptors=16KB 4GB*16KB =64TB
The 80386 was a third generation version of the 8086/8088 microprocessor. The second generation was the 80286, adding protected mode. The 80386 added 32 bit mode, virtual 8086 mode, and flat 32 bit protected mode.The 80386 fixed the problem of the 80286 where existing object code was not compatible in protected mode because the meaning of the segment registers changed. The 80386 allowed the operating system to run in protected mode while presenting the process with a virtual 8086 environment where the segment registers worked as before. This was a stop-gap measure that worked until the full implementation of a true 32 bit flat memory model operating system and software.
There are several differences between the 8086 and the 80386. Two notable differences: 1.) the 8086 is a 16 bit computer, while the 80386 is a 32 bit computer, and 2.) the 8086 does not support virtual addressing while the 80386 does.8086 is 8 bit processor and 80386 is 16 bit processor
The differences are given below: 80286 1. Low data bus width (16 bit) 2. Returning from protected mode to real mode is hard and complicated. 3. Small RAM/Memory 80386 1. High data bus width (32 bit) 2. Easy for 80386 3. Big RAM / Memory (Real memory = 4GB and virtual memory= 64TB)
The Intel 80386 is a 32-bit processor.
In order to interface more than 64K of memory using the 085, you would need an external address register, perhaps maintained by the 8255, which contained an offset register for part of the memory address space. This would be similar to how the 8086/8088 processors implemented expanded memory before using the 80386 and above processors.
Comparison between micro processor Intel and Motorola
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The 80386 Intel chip
To switch from real mode to protected mode in the 80386, set the PE bit in the MSW in CR0, and then immediately execute a JMP to flush the prefetch queue.
Segmentation concept is first introduced in 8086 microprocessor
The physical address is the final address that is presented to the bus, at the pins of the microprocessor chip, to form the address of the desired item in memory.In the 8085, physical and effective addresses are one and the same.In the 8086/8088, the physical address is the effective address plus 16 times one of the segment registers.In higher level processors, such as the 80386 and beyond, the physical address is formed by lookup of the effective address in a page table to convert from virtual/effective address to physical, or linear, address.The effective/virtual address is the address generated by the instruction and the programmer, without regard to any underlying addressing scheme. This is the address used when considering the "programming model", in "user mode".