The question is defective. It talks about plural 'lights', but it doesn't tell how many
there are, or in what configuration they're connected to the 12-volt power supply.
All of that stuff has a substantial effect on the correct answer. (But I don't think
the 10m length of the cable has any at all.)
When the length of the wire increases voltage drop across the wire will occur.There are two factors that can result in voltage drop. One diameter of the wire, two length of the wire.Voltage drop increases with increase in length of wire, whereas voltage drop decreases with increase in diameter (cross section area) of the wire.G.RAOAnswerIf you are asking what happens to the voltage across a length of wire when its length increases, the answer is nothinghappens! The voltage applied to the wire is determined by the supply, not by the load (i.e. the wire).
In AC current, its a quality measurement of voltage. If voltage is harmonious or "clean" you will see an equal wave length on both sides of your baseline. You can test and see this using an electrical scope.
You go to the NEC and look at the chart for developed length and the ambient temperature and the load factor and if it solid or stranded wire as stranded allows for more voltage
As the resistance in the wire increases due to the longer length the voltage drop across the wire resistance increases. This leaves less voltage across the load. To overcome this voltage drop usually a larger size wire which has less resistance is used. A safe nominal figure for voltage drop is to keep it at 3% of the line voltage.
Basic Telephony cable is manufactured with a built in capacitance of 0.084uF (microfarads) per mile on 22-24AWG (for example) wire. Basic cable length can be estimated with a voltmeter. Messuring the amount of voltage discharged when placing the wire to ground, discharging the stored voltage in the wire.
It just means length.
The longer you strech the arc, the smaller the voltage. Current rises though.
When the length of the wire increases voltage drop across the wire will occur.There are two factors that can result in voltage drop. One diameter of the wire, two length of the wire.Voltage drop increases with increase in length of wire, whereas voltage drop decreases with increase in diameter (cross section area) of the wire.G.RAOAnswerIf you are asking what happens to the voltage across a length of wire when its length increases, the answer is nothinghappens! The voltage applied to the wire is determined by the supply, not by the load (i.e. the wire).
Voltage does not have a waveform. The waveform is based upon the frequency of the voltage or current. A battery (any voltage) does not waveform, however the voltage coming into your house (US) has a frequency of 60 Hz. The length of the 60 hz waveformLength (in centimeters) = (3 x (10 ** 10))/ Frequency in hz =500 000 000 cm
Let's start with the correct terminology. The three energised, or 'hot', conductors are called 'line' conductors (not 'phase') conductors. which (surprise, surprise!) is why the voltages across them are called 'line voltages'.In the case of a star (wye) connected, three-phase, four-wire, system each phase is connected between a line and the neutral. And, yes, the line voltage is indeed root-3 (or 1.732) times the phase voltage.If the lines are labelled a, b, c, and the neutral is labelled N, then line voltage Vab is equal to the phasor (vector) sum of phase voltage Van and phase voltage Vnb, which are displaced from each other by 60 electrical degrees. The length of the resulting phasor is 1.732 times either of these phase voltage.
No, the resistance is fixed by the cross section and length of the conductor and does not vary with voltage.
30,000V for each centimeter in length. So for a spark of 2 centimeters that implies the voltage is 60,000V
In AC current, its a quality measurement of voltage. If voltage is harmonious or "clean" you will see an equal wave length on both sides of your baseline. You can test and see this using an electrical scope.
If the coil is powered with DC voltage, an inductive voltage is created anytime power to the coil is de-energized. The inductive voltage is called an inductive kick and it is up to ten times the applied voltage and is in reverse polarity to the applied voltage. A diode or other type of suppression device must be connected across the coil of the solenoid to protect any other electronic components in the circuit that may be damaged by this voltage. The diode is connected in reverse bias across the DC solenoid coil so that when voltage is applied in normal polarity, the diode does not provide a path for current. When the solenoid coil is de-energized, the inductive voltage is the opposite polarity to the power supply, so it will flow through the diode and back into the coil. Since the coil is made of a large length of wire. the energy of the inductive voltage will be dissipated as it moves through the wire. This will render the excessive inductive voltage harmless. The fact that the inductive voltage will travel through the diode in the forward bias direction means the 0.7-1 volt drop across the diode junction will also limit the V=< (dv/dt) surge. Fig. 4 (below) illustrates an example of the diode connected across the coil of a solenoid that is powered with DC voltage.
Voltage loss. On a long run you will loose some voltage so it is sometimes necessary to increase the wire size to compensate for the voltage loss. This loss of voltage will cause a light to be dim as it is not receiving the correct voltage that is was designed to use.
By changing the length of wire, say reducing it, the resistance will drop and that will increase current flow but the voltage is less likely to change V=IR.
You go to the NEC and look at the chart for developed length and the ambient temperature and the load factor and if it solid or stranded wire as stranded allows for more voltage