0
What else can I help you with?
What is the relationship between mass of a solid object and the volume?
There is no direct relationship between how much mass an object has and it's volume. That is, mass plays no part in calculating the volume, and volume plays not part in determining mass. However, they are related by the equation to calculate the density. Density=Mass/Volume.
How do you find the density of an object if you have the volume and mass?
Divide the mass by the volume. The quotient is the density. Don't throw away the units ... they're part of the answer.
What is the relationship between the volume and the buoyancy?
Density = mass / volume. An object will float if it has less density than the fluid in which it is placed. The buoyant force is equal to the volume (this may be the submerged part of the volume) times the density of the displaced fluid.
What is the relationship between density and volume and buoyancy?
Density = mass / volume. An object will float if it has less density than the fluid in which it is placed. The buoyant force is equal to the volume (this may be the submerged part of the volume) times the density of the displaced fluid.
Why does changing the shaper of an object have no effect density of that object?
As "density = mass/volume" or "D=m/V", the density of an object will remain the same unless the mass changes (which is unlikely) or the volume changes (more likely). When an object changes shape, it usually keeps the same volume, unless it is stretched or squashed. Therefore, changing the shape of an object will not necessarily change its density.If the mass of the object did in fact change, It would usually be a result of part of the object breaking off, in which case the volume would also be reduced, leaving the density at the same value.
What is the difference between surface and density?
You cannot use surface area to calculate density. Density is a calculation comparing TOTAL area and weight of an object. In short you must use the total volume of the object when calculating the density.
How can the part of the specimen floats in water?
If a part of a specimen floats in water, it likely has a lower density than water. The density of an object is determined by its mass and volume. Therefore, the part of the specimen that is floating likely has a volume that displaces enough water to support its mass, resulting in it floating.
Why does the density of an object have no effect after it is changed?
If you mean why does the density of an object not change when it undergoes a physical change such as a change of shape then the answer is because density is a chemical trait found by dividing the mass by the volume and if you modify the volume then the mass will also be modified for example water has a density of 1 g/cm^3 meaning if you have 3 grams of water it takes up 3 cm^3 even if you change the mass when you change the mass you are also changing the volume same goes if you change the volume you change the mass. In other words mass and volume are relative to each other and when you divide mass by volume you get a number the density the density represents a ratio for water the density is 1 g/cm^3 the ratio of mass to volume is 1:1,1/1, or 1 to 1 meaning for every cm^3 you have of water you will have an equivalent amount of grams. 1 to 1 1 part mass 1 part volume but that is just for water every substance has a density and they rarely if ever are equal.
What is the procedure for finding the volume of a regular object?
If the object shape can be approximated as being comprised of several simple geometric shapes one can just calculate the volume of each of these shapes based on their individual geometries. If the object is highly asymmetrical and it is not comprised of a series of geometrically simple shapes then you can do the following: 1) calibrate a large vat or container by marking the volume at various levels. 2) fill the container (not to the top) with water. 3) submerge the object in the container 4) calculate the change in volume. 5) the volume of the object is equal to the change in volume in the container If the object is too big to be placed in a vat but the object has a homogeneous density then one can do the following: 1) break off a small piece of the object 2) measure the mass of this small sample piece 3) measure the volume of the small object sample using steps 1-5 above 3) calculate the density of the homogenous material that comprises the sample density=mass/volume 4) measure the mass of the entire object 5) calculate the total volume: volume=mass/density 6) if you want to be precise you can add to this the sample volume that you cut away in step 1 If the object can't be submerged and is made up of several parts with different homogeneous densities then repeat steps 1-6 for each part of the object and sum the values of the volume for each part of the object. (Note: do not use this method if you value keeping the object in one piece.) If the object can't be submerged and has a variable density throughout its volume then do the following: 1) create a mold of the object 2) fill the mold with water 3) calculate the volume of water required to fill the mold
What part on an object will determine whether it floats?
it is not a part it is the bouancy of the material
What is equal to the volume of water an object displaces?
The volume of water an object displaces is equal to the volume of the object itself, as stated by Archimedes' principle. This principle explains that the volume of fluid displaced by an object immersed in a fluid is equal to the volume of the object.
Why is an object's density expressed as a combination of two unit's?
Density is expressed of two units as it consist of two aspects, weight and space. When interested in density, someone needs to know how much an object weighs and how much space it takes (mass per unit of volume). The density of an object is expressed as mass/volume because that is the formula for density. d = m/v. So, after you divide the coefficients of the mass and volume you will have the m/v part still left. example: 2.7g/6.1cm3 = .44g/cm3 OR 4.4x10-1g/cm3
