Balanced Equation:
Co2(S04)3(aq) + 3Na2CO3 (aq)Ã 3Na2SO4 (aq) + Co2(CO3)3 (s)
Next, convert the grams of sodium carbonate to moles5.00 g Na2CO3 x (1molNa2Co3/105.99 g Na2CO3) =
0.0472 mol Na2CO3
From this, determine the moles of Co2(S04)3
0.0472 mol Na2CO3 x (1mol Co2(S04)3/3mol Na2CO3) = 0.0157 mol Co2(S04)3
Finally, determine volume of Co2(S04)3
V = 0.0157mol/0.2500 mol/L = 0.0628 L Co2(S04)3
To calculate the volume of 0.2500 M cobalt III sulfate needed to react completely with 5.00 g of sodium carbonate, you first need to determine the molar mass of sodium carbonate (Na2CO3) and cobalt III sulfate [Co2(SO4)3]. Then, use the given mass of sodium carbonate to calculate the number of moles, and from there, determine the volume of cobalt III sulfate needed based on the stoichiometry of the balanced chemical equation.
Co2(SO4)3 + 3Ca(OH)2---> 2Co(OH)3+ 3CaSO4 Co Sulfate and Ca hydroxide react in 1:3 ratio. Moles of Ca Hydroxide=0.0007875mol Moles of CoSulfate needed=0.002625 Volume=1.05
To determine the volume of .25M cobalt(III) sulfate required to react completely with 25 mL of .0315M calcium hydroxide, you need to write and balance the chemical equation for the reaction. Then, use the stoichiometry of the balanced equation to determine the amount of cobalt(III) sulfate needed based on the moles of calcium hydroxide used in the reaction. Finally, use the concentration of cobalt(III) sulfate to calculate the volume needed.
The name of the compound Co2(SO3)3 is cobalt(III) sulfate.
There are three types of elements present in cobalt(II) carbonate, which are cobalt, carbon, and oxygen.
The formula for cobalt(III) carbonate is Co2(CO3)3.
Al(SO4)3 ^That is completely wrong. Al(SO4)3 is aluminum sulfate cobalt ii sulfide is CoS actually you both are wronq. its really CoSO4 <<< cobalt sulfate Wow. He/She was right. Your totally wrong. Cobalt (II) Co^2+ and Sulfide is S^2- So the answer is CoS. Signs cancel themselves out..
The name of the compound Co2(SO3)3 is cobalt(III) sulfate.
There are three types of elements present in cobalt(II) carbonate, which are cobalt, carbon, and oxygen.
The formula for cobalt(III) carbonate is Co2(CO3)3.
There are no compounds in Cobalt. It is completely impossible, because Cobalt is an element, and compounds are made up of elements. If this is what you meant to ask, then there a a lot of compounds with Cobalt in them. One example is Cobalt (III) Fluoride, chemical formula CoF3. Any compound with a "Co" (the "C" must be capitalized and the "o" must lowercase) in it contains Cobalt.
Al(SO4)3 ^That is completely wrong. Al(SO4)3 is aluminum sulfate cobalt ii sulfide is CoS actually you both are wronq. its really CoSO4 <<< cobalt sulfate Wow. He/She was right. Your totally wrong. Cobalt (II) Co^2+ and Sulfide is S^2- So the answer is CoS. Signs cancel themselves out..
A cobalt sulfate solution is typically blue in color.
The chemical formula for cobalt(II) hydrogen carbonate is Co(HCO3)2.
Yes, cobalt form many chemical compounds as cobalt nitrate, cobalt chloride, cobalt sulfate, cobalt sulfide, etc.
When cobalt II sulfate reacts with sodium hydroxide, cobalt II hydroxide is formed as a blue precipitate. The chemical equation for this reaction is: CoSO4 + 2NaOH -> Co(OH)2 + Na2SO4.
cobalt carbonate
Yes, cobalt form many chemical compounds as cobalt nitrate, cobalt chloride, cobalt sulfate, cobalt sulfide, etc.
The decomposition of cobalt carbonate results in the formation of cobalt oxide (CoO) and carbon dioxide (CO2) gas. This chemical reaction can be represented by the equation: CoCO3 -> CoO + CO2.