volume of a regular right circular cylinder is V=pi(r2)h
since the radius is (a) then the height of the circular cylinder would be (2a)
so the volume of the largest possible right circular cylinder is...
V=2(pi)(r2)(a)
with (pi) being 3.14159
with (r) being the radius of the circle on the top and bottom of the cylinder
with (a) being the radius of the sphere
Find the dimensions of the rectangle of largest area that can be inscribed in a circle of radius a in C programming
Let the radius of the largest sphere that can be carved out of the cube be r cm.The largest sphere which can be carved out of a cube touches all the faces of the cube.∴ Diameter of the largest sphere = Edge of the cube⇒ 2r = 7 cm∴ Volume of the largest sphere
1357.2
90
If you're talking about a pie chart, each wedge in the circle is demonstrating a percentage. The largest wedge would be the largest percentage, the smallest would be the smallest percentage.
(4/27)*pi*R3*tan(x) R being the radius of the base of the cone.
Find the dimensions of the rectangle of largest area that can be inscribed in a circle of radius a in C programming
Let the radius of the largest sphere that can be carved out of the cube be r cm.The largest sphere which can be carved out of a cube touches all the faces of the cube.∴ Diameter of the largest sphere = Edge of the cube⇒ 2r = 7 cm∴ Volume of the largest sphere
A host cell
It is 2*r^2.
The biggest diameter that would fit is 20 ft.
The answer depends on the cylinder.
The largest rectangle would be a square. If the circle has radius a, the diameter is 2a. This diameter would also be the diameter of a square of side length b. Using the Pythagorean theorem, b2 + b2 = (2a)2. 2b2 = 4a2 b2 = 2a2 b = √(2a2) or a√2 = the length of the sides of the square The area of a square of side length b is therefore (√(2a2))2 = 2a2 which is the largest area for a rectangle inscribed in a circle of radius a.
it represents the nucleus
First, let us find the height of one side of the cube, we have; S= cube root of 64 S= 4. Since the diameter is 4 cm, the radius will be 2 cm. now, solve it by using the formula: V= PI.r squared . h V= 3.14. 2 cm squared. 4 cm V= 3.14. 16 v=50.24 cubic centimeter
the largest earthquake possibleis the larges earthquake possible
Approximately 5.66x5.66 in. Or root32 x root32