Top Answer

It's the equation of a straight line. Every point on the line is a

solution to the equation. There are an infinite number of them.

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04x + 3y = 7 y = [(-4)/3] x + 7/3

You need to organise your question properly. 3x+2y=4 4x + 3y= 7? Is 4 4x = 44x or 4-4x or 4+4x How can there be 2 equal signs in 1 equation?

4x - 3y = -7 Change all signs: -4x + 3y = 7 Add 4x to both sides: 3y = 4x + 7 Divide both sides by 3: y = (4/3)*x + 7/3 m = 4/3, b = 7/3

given is that 4x+3y=6(3x+3y)=7 i.e., 6(3x+3y)=7 &&& 4x+3y=7 ---------------(1) 3x+3y=7/6 x+y=7/18 _________(2) multiply eqn(2) by 4 4x+4y=28/18 -------------------------(3) (3)-(1) 4x+3y-4x-4y=7-(28/18) y= -98/18 substitute y in eqn(2) x-98/18=7/18 x=7/18+98/18 x=105/18. therefore x=105/18 : y= -98/18

Yes and their solutions are x = 41 and y = -58

(A): 4x + y = 7 (B): 2x - 3y = -7 2*(B) 4x - 6y = -14 Subtract from (A) 7y = 21 Divide both sides by 7: y = 3 Substitute in (A): 4x + 3 = 7 ie 4x = 4 or x = 1 Answer: x = 1 , y = 3

They are simultaneous equations and their solutions are x = 41 and y = -58

16x2 + 8x + 1 - 9y2 = (4x + 1)2 - (3y)2 which is a difference of two squares. = (4x + 1 + 3y)*(4x + 1 - 3y)

x+y=15, or y=15-x4x+3y=38Substitute y in 2nd equation with 15-x:4x+45-3x=38x=-7y=15-(-7)=22(-7,22)

x+y=154x+3y=384x+4y=604x+3y=38(4x+4y=60)-(4x+3y=38)-->(4x-4x+4y-3y=60-38)-->(0x+1y=22)-->[since 0x=0](1y[y]=22)given y=22and x+y=15x+22=15x=15-22=-7therefore ANSWER KEYX=-7 Y=22Checking answers4x+3y=38-28+66=38THEREFOREThis is correctIf you have problems please write a message on Its Me Ue's message board

Stating that it is an equilateral triangle, we are told that all sides are equal.This is another way of saying:4x - y = 7and2x + 3y = 7So this can be solved by eliminating one of those variables:2x + 3y = 7x = (7 - 3y) / 24((7 - 3y) / 2) - y = 714 - 7y = 7y = 1x = 2

4x-5y=20 x-3y=10 becomes x=3y-10 plug that into the first equation: 4(3y-10)-5y=20 12y-40-5y=20 7y=60 y=60/7 If x=3y-10, then x=3(60/7)-10 x=180/7 - 70/7 x=110/7

5y+14+y = 3y-7 5y+y-3y = -7-14 3y = -21 y = -7

3x+7=4x 7=4x-3x 7=x

If: 5x = 4x+7 Then: 5x-4x = 7 And: x = 7

4x plus 7 plus 3x equals 19 plus xx = 2

(1) x+y=15(2) 4x+3y=38From (1) one gets x=15 -y, put into(2)4(15-y)+3y=3860-4y+3y=3860-y=38y=22 then x=15-y=-7(-7,22) is the solution

We have the given equations 4x+y=7 2x-3y=-7 First we want to make it so that we have a variable with the same coefficient in both equations. We will use the x. so we have 4x+y=7 and 2x-3y=-7. We can multiply or divide both sides of either equation by the same number without changing the equation, so we will take 2x-3y=-7 times 2 2(2x-3y)=2(-7) distribute 4x-6y=14 now we can use elimination. 4x+y=7 -(4x-6y=-14) 7y=21 divide by 7 7y/7= 21/7 y=3 Now we plug 3 into one of the original equations. 4x+3=7 subtract 4x+3-3=7 -3 4x=4 divide 4x/4= 4/4 x=1 so, the solution to our system of equations is (1,3)

4x+7=9x+7 -5x=0 x=0

The solution pair is (-7, 22), demonstrated as follows: (1) x + y = 15 : given; (2)4x + 3y = 38 : given; (3)3x + 3y = 45 : equation (1), multiplied by 3; (4) x = -7 : equation (2), minus equation (3); (5) y = 22 : equation (1), minus equation (4).

4x + 7 = 6x -7 14=2x so x = 7 (plus a negative # is simply - that number)

x + y = 154x + 3y = 38from the first equation, y = 15-xsubstitute this value in the second equation as follows:4x + 3(15-x)= 384x + 45 - 3x = 38x + 45 = 38x = 38 - 45so, x = -7substitute this value to solve for y:y = 15 -xy = 15-(-7)y = 22

If 4x + 7 = 3... then x must equal -1

Let's see if I can answer this. 4X + 6Y + 3Y + 4W + 6X - 7W = (4 + 6)X + (6 + 3)Y + (4 - 7)W = 10X + 9Y - 3W

4x+7-8x=17-4x+7=17-4x=10x = -5/2

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