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V=I*R Where: V is voltage I is the current in ampers R is resistance in ohms. So, if the current is 15 A and the resistance is 5 ohms, then the voltage must be 15 A *5 ohms = 75 V.
volt drop and potential difference are effectively the same thing, although the term volt drop is usually used in reference of what voltage has to occur for a diode to conduct, or what volt drop is expected across a long wire etc, potential difference is used to refer to the difference in voltage over a potential divider.
15 amps 120 volts AC
To answer this question the voltage of the motor must be stated.
15/600 * 200
point 150 = 150/1000 = 3/20 point 015 = 15/1000 = 3/200
15 is a factor of 150, 150 is a multiple of 15.
V=I*R Where: V is voltage I is the current in ampers R is resistance in ohms. So, if the current is 15 A and the resistance is 5 ohms, then the voltage must be 15 A *5 ohms = 75 V.
15% of 150 = 22.5
$127.515% off of $150= 15% discount applied to $150= $150 - (15% * $150)= $150 - (0.15 * $150)= $150 - $22.5= $127.5
135 It is 15 more than 120 and 15 less than 150
150 10 x 15 = 150 15 x 10 = 150 25 x 6 = 150
15
150-135 = 15
150 = 15*10 = 3*5*5*2 = 2*3*52
The difference between the highest and lowest numbers:eg. The range between 5 and 15 is 10.eg. The range between 125, 150 and 175 is 150. (175-125)
volt drop and potential difference are effectively the same thing, although the term volt drop is usually used in reference of what voltage has to occur for a diode to conduct, or what volt drop is expected across a long wire etc, potential difference is used to refer to the difference in voltage over a potential divider.