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because ch4 has an octett and bh3 not so it dimerises to b2h6
6.3(mol) * 13.83 (g·mol−1)= 87.1 gram BH3
3
BH3 is non polar.Inter moleculer forces are much weaker Wander Voals forces.NH3 have hydrogen bonds among molecules.They are very strong comparing to Vander Woals forces.So NH3 have high boiling point.
The only thing I can think of is the size match between Cl and the B or Al; there's more likely to be an interaction between the vacant AO on Al than B and the Cl lone pairs because the AOs are better matched in energy and size, making the bonding interaction more favourable. I might be talking rubbish but that's one theory anyway! A.P.
120 degrees
A trigonal planar molecule such as sulfur trioxide (SO3) or boron trihydride (BH3) has a trigonal planar shape. Trigonal pyramidal molecules such as ammonia (NH3) have bond angle closer to 107 degrees.
BH3 is electron pair acceptor
BH3 is non polar because the bond angles are all 120 degrees and cancel out. I know this one was tricky! think of it this way, BH3 is trigonal planar. The "B" atom is surrounded by 3 "H" atoms. all these H atoms are partially positive. Because if that, the outer part of the molecule is uniformly positive. so another atom "looking at" BH3 would "see" the same charge from all sides of the molecule. it works in the same way for CCL4 and CH4 and other symmetric molecules.
BH3 is a strange molecule since Boron doesn't have an octet rule, but rather a sexet rule meaning 6 valence electrons as opposed to 8 for it's valence shell. BH3 is a metal, Boron, and three nonmetals, Hydrogen, so it is an ionic bond.
BH3 has a trigonal planar shape with 120 angles.
This carbocation which only has six electrons is isoelectronic with BH3 and is believed to have a similar structure as gaseous molecular BH3, planar with bond angles of 120 0. The hybridisation would be sp2 with and empty p orbital.
5,00 g of BH3 is equal to 0,36 moles.
because ch4 has an octett and bh3 not so it dimerises to b2h6
6.3(mol) * 13.83 (g·mol−1)= 87.1 gram BH3
BH3
it is BH3