The bond angle decreases from NH3 to BH3 primarily due to the difference in the presence of lone pairs and the types of bonding orbitals involved. NH3 has a lone pair on nitrogen, which exerts repulsion and pushes the hydrogen atoms closer together, resulting in a bond angle of about 107 degrees. In contrast, BH3 has no lone pairs on boron and adopts a trigonal planar geometry with bond angles of approximately 120 degrees. However, the effective repulsion from the empty p-orbitals in BH3 leads to a slight decrease in bond angle compared to the ideal trigonal planar geometry.
BH3 polymerizes due to its ability to form coordinate covalent bonds with other BH3 molecules, creating a network of boron atoms through the sharing of electron pairs. This is facilitated by the electron-deficient nature of boron, which allows it to accept electrons and bond with other BH3 units. In contrast, CH4 (methane) has a stable tetrahedral structure with strong single covalent bonds between carbon and hydrogen, lacking the ability to further bond or react in a way that would lead to polymerization. Thus, the chemical properties and bonding characteristics of BH3 allow for polymerization, while CH4 remains a stable, non-reactive molecule.
because ch4 has an octett and bh3 not so it dimerises to b2h6
6.3(mol) * 13.83 (g·mol−1)= 87.1 gram BH3
In the Lewis dot structure for BH3, there should be 3 bonds drawn. Each hydrogen atom forms a single covalent bond with the boron atom. Boron has three valence electrons, so it can form three bonds with the hydrogen atoms.
BH3 is non polar.Inter moleculer forces are much weaker Wander Voals forces.NH3 have hydrogen bonds among molecules.They are very strong comparing to Vander Woals forces.So NH3 have high boiling point.
BH3 has a bond angle of 120 degrees.
A trigonal planar molecule such as sulfur trioxide (SO3) or boron trihydride (BH3) has a trigonal planar shape. Trigonal pyramidal molecules such as ammonia (NH3) have bond angle closer to 107 degrees.
BH3 is a strange molecule since Boron doesn't have an octet rule, but rather a sexet rule meaning 6 valence electrons as opposed to 8 for it's valence shell. BH3 is a metal, Boron, and three nonmetals, Hydrogen, so it is an ionic bond.
BH3 is non polar because the bond angles are all 120 degrees and cancel out. I know this one was tricky! think of it this way, BH3 is trigonal planar. The "B" atom is surrounded by 3 "H" atoms. all these H atoms are partially positive. Because if that, the outer part of the molecule is uniformly positive. so another atom "looking at" BH3 would "see" the same charge from all sides of the molecule. it works in the same way for CCL4 and CH4 and other symmetric molecules.
BH3 has a trigonal planar shape with 120 angles.
To find the number of moles of BH3 in 5.00 g of BH3, you first need to determine the molar mass of BH3. The molar mass of BH3 is 11.83 g/mol. Next, divide the given mass by the molar mass to find the number of moles. Therefore, in 5.00 g of BH3, there are 5.00 g / 11.83 g/mol ≈ 0.423 moles of BH3.
BH3 polymerizes due to its ability to form coordinate covalent bonds with other BH3 molecules, creating a network of boron atoms through the sharing of electron pairs. This is facilitated by the electron-deficient nature of boron, which allows it to accept electrons and bond with other BH3 units. In contrast, CH4 (methane) has a stable tetrahedral structure with strong single covalent bonds between carbon and hydrogen, lacking the ability to further bond or react in a way that would lead to polymerization. Thus, the chemical properties and bonding characteristics of BH3 allow for polymerization, while CH4 remains a stable, non-reactive molecule.
it is BH3
because ch4 has an octett and bh3 not so it dimerises to b2h6
Among the options provided, AsH3 (arsine) would make a good electron pair donor in the formation of a coordinate covalent bond. This is because arsenic has a lone pair of electrons available for donation, allowing it to act as a Lewis base and form a coordinate covalent bond with a Lewis acid.
6.3(mol) * 13.83 (g·mol−1)= 87.1 gram BH3
In the Lewis dot structure for BH3, there should be 3 bonds drawn. Each hydrogen atom forms a single covalent bond with the boron atom. Boron has three valence electrons, so it can form three bonds with the hydrogen atoms.