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We're not sure what the question means when it says "into" displacement.
For that matter, we're not absolutely sure what 'W' stands for.
Plus, to be honest, we don't see a question here.
But "... into ..." is still troubling us.
Perhaps this will help:
Work is defined as (force) multiplied by (distance through which the force acts)
What else can I help you with?
What is the formula for solving work?
The formula for work is work = force x distance x cos(theta), where force is the applied force, distance is the displacement over which the force is applied, and theta is the angle between the force and the direction of motion.
How is work related to force and displacement discuss in term of base units?
In the International System of Units (SI), work is defined as the product of force and displacement, where work (in joules) equals force (in newtons) times displacement (in meters). The base units for force is the newton (N) and for displacement is the meter (m), therefore work is measured in newton-meters (N*m), which is equivalent to joules.
How is work done by a force measured when force is in direction of displacement?
Work done by a force when the force is in the direction of displacement is calculated as the product of the force and the displacement, multiplied by the cosine of the angle between them. Mathematically, work done (W) = force (F) × displacement (s) × cos(θ), where θ is the angle between the force vector and the displacement vector.
What do muscles do all day?
Work! w=force times displacement.
How is work done by a force measures?
Work done by a force is measured as the product of the force applied on an object and the displacement of the object in the direction of the force. Mathematically, work (W) is calculated as W = force (F) × displacement (d) × cos(θ), where θ is the angle between the force and the displacement vectors. The unit of work is the joule (J).
What is the work done when the direction of displacement and the direction of force acting on the body are perpendicular to each other?
according to physics it will be zero work W=F.S (dot product of force and displacement) from vector algebra W= F*S*cos ( angle between force and displacement) W = F * S * COS (90) BUT cos(90)= 0 so W=0
What is the product of the force and the displacement?
The product of force and displacement is defined as work. It is a scalar quantity that measures the transfer of energy to an object when a force is applied to move it over a certain distance in the direction of the force. The formula to calculate work is W = F * d * cos(theta), where F is the force applied, d is the displacement, and theta is the angle between the force and the displacement.
What is the formula for the work?
W=Fdf=ma
What is the physical science definition for work?
In physical science, work is defined as the product of the force applied to an object and the displacement it undergoes in the direction of the force. Mathematically, work is calculated as W = F * d * cos(theta), where W is work, F is force, d is displacement, and theta is the angle between the force and displacement vectors. Work is a scalar quantity measured in joules.
What angle do you use in work equation?
In the work equation, the angle used is the angle between the direction of the force applied and the direction of displacement. The work done (W) is calculated using the formula ( W = F \cdot d \cdot \cos(\theta) ), where ( F ) is the magnitude of the force, ( d ) is the displacement, and ( \theta ) is the angle. If the force is in the same direction as the displacement, ( \theta ) is 0 degrees, and the work done is maximized. If the force is perpendicular to the displacement, the work done is zero.
How is the direction of the vectors involved in the definition of work?
A definition of work W: W = ⌠F∙dsWhere F is a force vector that is dot-multiplying (scalar product) the differentialdisplacement vector dS. The result is the work W, a scalar, done by the force thatproduced the displacement. But notice that the scalar product of both vectors willonly consider the force component that is collinear with the displacement vector.
Can an object do work when net force on it is zero?
Work is the scalr product of Force F and displacement D, W=F.D = fdcos(x) if the net force is zero W= 0.d= 0 or no work/
