You are given the following chemical rection
N
2
(
g
)
O
2
(
g
)
→
2
N
O
(
g
)
Provide an explanaition for why this reaction is endothermic (both conceptual, and mathematical);
Is this reaction spontaneous at 298 K?
If not, at what temperature does it become spontaneous?
Data given:
Δ
H
∘
f
=
90.4
kJ/mol
for
N
O
and
Δ
S
reaction
=
24.7
J/K
Let's start with the math to get it out of the way. A reaction is said to be endothermic if its change in enthalpy,
Δ
H
reaction
, is positive. We can calculate this change in enthalpy from what the data provides us.
Δ
H
reaction
=
2 moles NO
⋅
90.4
k
J
m
o
l
−
(
1 mole
N
2
)
⋅
0
k
J
m
o
l
−
(
1 mole
O
2
)
⋅
0
k
J
m
o
l
Δ
H
reaction
=
2 moles NO
⋅
90.4
k
J
m
o
l
=
180.8
k
J
The trick here was to be aware of the fact that the enthalpy of formation (
Δ
H
∘
f
) for elements is zero.
Since
Δ
H
reaction
>
0
, the reaction is indeed endothermic.
Conceptually, this reaction is endothermic despite the fact that a bond (between
N
and
O
) is formed; this happens because the
N
2
molecule has its two atoms bonded together by a very strong triple bond, which means that more energy must be put into breaking this bond than is released when the
N
O
molecule is formed.
Now, in order for a reaction to be spontaneous, the sign of
Δ
G
We can therefore determine this reaction's spontaneity by using
Δ
G
reaction
=
Δ
H
reaction
−
T
⋅
Δ
S
reaction
Δ
G
reaction
=
180.8
⋅
10
3
J
−
298
K
⋅
24.71
⋅
J
K
=
173.4
k
J
The reaction is not spontaneous at this temperature. We can determine at what temperature the reaction starts to be spontaneous by setting
Δ
G
reaction
=
0
.
0
=
Δ
H
reaction
−
T
⋅
Δ
S
reaction
T
=
Δ
H
reaction
Δ
S
reaction
=
180.8
⋅
10
3
J
24.71
J
K
=
7317
K
This reaction becomes spontaneous at
7317
K
.
As a conclusion, questions about endothermic or exothermic processes revolve around
Δ
H
,
Δ
S
, and
Δ
G
Any endothermic reaction, for instance photosynthesis.
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