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To solve this problem, you will need to use the balanced chemical equation provided to determine the mole ratios between the reactants and products.

First, convert the volume of H3PO4 to liters by dividing by 1000 mL/L:

750 mL H3PO4 / 1000 mL/L = 0.750 L H3PO4

Next, convert the concentration of H3PO4 to moles/L:

6.00 M H3PO4 = 6.00 mol/L H3PO4

Now, use the volume and concentration to calculate the number of moles of H3PO4:

0.750 L H3PO4 * 6.00 mol/L H3PO4 = 4.50 mol H3PO4

Since the chemical equation shows a 1:1 mole ratio between H3PO4 and Ca(OH)2, there must be 4.50 mol Ca(OH)2 as well.

To determine the mass of each product, you will need to know the molar masses of each compound. The molar mass of H3PO4 is 98.00 g/mol, and the molar mass of Ca(PO4)2 is 212.09 g/mol.

Therefore, the mass of H3PO4 produced in the reaction is:

4.50 mol H3PO4 * 98.00 g/mol = 434.00 g H3PO4

And the mass of Ca(PO4)2 produced in the reaction is:

4.50 mol Ca(PO4)2 * 212.09 g/mol = 953.41 g Ca(PO4)2

These are the masses of each product that would be produced if 750 mL of 6.00 M H3PO4 reacts according to the given chemical equation.

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Judy Watson

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2y ago

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