999
To find a two-digit number multiplied by a one-digit number that equals 27, we can consider the factors of 27. The two-digit number must be 27 divided by a one-digit factor. The valid combinations are 27 = 9 × 3, where 9 is a one-digit number, and 27 divided by 3 gives us 9, which is also a one-digit number. Therefore, a valid two-digit number multiplied by a one-digit number to get 27 does not exist since 27 itself is a two-digit number.
The value of the ones digit in 27 is 7.
To find the units digit of (27^{27}), we can look at the units digit of (27), which is (7). We then need to find the units digit of (7^{27}). The units digits of the powers of (7) cycle every four terms: (7^1 = 7), (7^2 = 49) (units digit (9)), (7^3 = 343) (units digit (3)), and (7^4 = 2401) (units digit (1)). Since (27 \mod 4 = 3), the units digit of (7^{27}) is the same as that of (7^3), which is (3). Thus, the units digit of (27^{27}) is (3).
The greatest 3-digit number is 999. 9+9+9 = 27 The sum of the greatest 3-digit number is 27.
There are 27 of them.
The product of 3 times 9 is 27. In the number 27, the tens digit is 2.
-27
Only one . . . 999 .
24 and 3
-307
27
27, 57, 77 and 87.