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What Is the sin of a righ triangle if the sides are 25 20 and the base is 15?
Wiki User
∙ 12y ago
Triangles don't have sines, but angles do.
In your right triangle . . .
-- the sine of the right angle is 1.000 .
-- The sine of the smallest angle is 0.600, so it's about 36.87 degrees.
-- The sine of the remaining angle is 0.800, so it's about 53.13 degrees.
Wiki User
∙ 12y ago
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The base of an isosceles triangle is 3 cm in lenght and the angle opposite the base measure 64 degrees Find the lenght of each of the component sides?
Since the vertex angle is 64⁰, the base angle is 58⁰, (180⁰ - 64⁰ )/2. Using the Law of Sines we have side length/sin 58⁰ = 3 cm/sin 64⁰ (multiply by sin 58⁰ to both sides) side length = (3 cm)(sin 58⁰)/sin 64⁰ ≈ 2.8 cm Thus, the congruent sides of the given isosceles triangle have a length of 2.8 cm.
How do you construct an isosceles triangle when base and angle at the vertex is given?
First find 180 minus the vertex angle and divide that by 2 to get the other angles. Then solve the other sides by using sin(vertex angle)/base=sin(other angles)/other sides.
What is The sum of any 2 sides of an isosceles triangle?
Depends from the given information. For example, if it is given the measure of the angle base θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/cos θ If it is given the measure of the angle base θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/sin θ If it is given the measure of the vertex angle θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/sin θ/2 If it is given the measure of the vertex angle θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/cos θ/2 If it is given the length measures of the base b and the height h, the sum of the sides a of the isosceles triangle equals to 2a = √(h4 + b2) (from the Pythagorean theorem)
Can an equiangular triangle be scalene?
No. An equiangular triangle is always equilateral. This can be proven by the Law of Sines, which states that sin A / a = sin B / b = sin C / c, where A, B and C are angles of a triangle and a, b and c are the opposing sides of their corresponding angles. If A = B = C, then sin A = sin B = sin C. Therefore for the equation to work out, a = b = c. Therefore the eqiangular triangle is equilateral, and therefore not scalene, which requires that all sides of the triangle be of different lengths.
What is relations among the sides of a triangle?
There are several. Some of the more common ones are: Any two sides of a triangle must be larger than the third. If a, b and c are the lengths of the sides and A, B and C are the angles oppostie these sides, then sin(A)/a = sin(B)/b = sin(C)/c a2 = b2 + c2 - 2bc*Cos(A)
How Dividing equilateral triangle?
This is a fun question. If the triangle rests on one of its sides as a base, then the altitude of the triangle, a line drawn from the apex of the triangle to the base, divides the triangle into two right angle 30o,60o, 90o, triangles. For convenience let each of the equal sides of the triangle 2 units. Then Pythagorus tells us that the base of each of these right triangles is 1 unit and the altitude is √3. This leads directly to sin(30o) cos(60o) 1/2 and cos(30o) sin(60o) √3/2 0.866 rounded. You can also use one of these right angle triangles to find the sine and cosine of 15o but the algebra gets a little messy.
How do you write a program to find the area of a triangle?
The area of a triangle is one half base times height, so you would write a program to input the base and height, giving the option to stop, calculating and printing the area, and then looping to repeat as desired.
What are the lengths of the missing sides of a 30-60-90 triangle if the longer leg of the triangle is 18 centimeter?
The longest side of the triangle will always be opposite the largest angle, which is 90° in this case. We can use the sine law to work out the other sides with that: sin(90°) / 18 = sin(60°) / x = sin(30°) / y 1/18 = sin(60°) / x x = 18 sin(60°) x = 18√3 / 2 x = 9√3 1/18 = sin(30°) / y y = 18 sin(30°) y = 9 So the triangle has a sides of 9 and 9√3, with a hypotenuse of 18
What is the approximate length of the base of an isosceles triangle if the congruent sides are 3 feet and the vertex angle is 35 degress?
The median of an isosceles triangle from its apex is also the perpendicular bisector of the base. This line divides the triangle into two congruent right angled triangles whose hypotenuse is 3 feet and whose apical angle is 35/2 = 17.5 degrees. If the base of the original triangle was 2b cm then sin(17.5) = b/3 so that b = 3*sin(17.5) = 0.9cm so that the base was 2b = 1.8 feet Alternatively, you could use the sine rule on the triangle:
How do you calculate the area of anisosceles trapezoid if you only know the width of the base and the length and angle of the sides?
One way would be as follows: Let b represent the length of the base, l the length of each of the two sides, and theta the angle between the base and the two sides of length l. Now drop a perpendicular line from each vertex at the top of the trapezoid to the base. This yields two right triangles and a rectangle in the middle. The height of each right triangle (as well as the height of the rectangle) equals l*sin(theta) [because sin(theta)=opposite/hypotenuse] and the length of the base of each right triangle is l*cos(theta). The base of the rectangle is b minus the lengths of the two right triangles. Area of the trapezoid=2*area of each right triangle+area of the rectangle=2*(1/2)*(l*sin(theta)*l*cos(theta))+(b-2*l*cos(theta))(l*sin(theta))=)*(l*sin(theta)*l*cos(theta))+(b-2*l*cos(theta))(l*sin(theta))=b*l*sin(theta)-l2*sin(theta)*cos(theta)
What is the relationship between two shorter sides on a triangle and one longer side?
If given that:a, b, and c are sides for any triangle,A, B, and C are the angles opposite of their sides,assuming c is the longest side, thenc2 = a2 + b2 -2ab*cos(C) (Law of Cosines)c/sin(C) = a/sin(A) = b/sin(B) (Law of Sines)In a right triangle,a2 + b2 = c2(Pythagorean Theorem)
How do you find the height of a triangle without given area?
Answer the answer is Herons formula:Area=sqrt(sin(sin-a)+(sin-b)+(sin-c) where a ,b, c are the measurement of the sides.just input the measurement of the sides in the formula and you will have your answer.here you can calculate the area of a triangle with out height.
