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What acceleration does a rocket need to reach a speed of 230meters per second at a height of 1.0km?
Wiki User
∙ 10y ago
26.45ms-2
Wiki User
∙ 10y ago
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A 2.15 kg book is dropped from a height of 1.6 meters what is its acceleration?
If air resistance can be ignored, the acceleration is 9.82 meters per second square. Note that to get this result, neither the mass of the book, nor the height from which it is dropped, is relevant.If air resistance can be ignored, the acceleration is 9.82 meters per second square. Note that to get this result, neither the mass of the book, nor the height from which it is dropped, is relevant.If air resistance can be ignored, the acceleration is 9.82 meters per second square. Note that to get this result, neither the mass of the book, nor the height from which it is dropped, is relevant.If air resistance can be ignored, the acceleration is 9.82 meters per second square. Note that to get this result, neither the mass of the book, nor the height from which it is dropped, is relevant.
Why do we a use the units meters per second squared when we talk about acceleration?
For every second of acceleration the velocity is increased by that acceleration.
If a bowling ball and a Nerf ball dropped at the same time and height what would the acceleration be?
it would be 9.8 meter per second. anything that isn't subject to air resistance(like paper) will fall at this rate for this is the acceleration of gravity,
How do you Calculate G forces with only Acceleration given?
You divide the given acceleration by the standard acceleration due to Earth's gravity. If the acceleration is in meters per second square, you divide by 9.8.You divide the given acceleration by the standard acceleration due to Earth's gravity. If the acceleration is in meters per second square, you divide by 9.8.You divide the given acceleration by the standard acceleration due to Earth's gravity. If the acceleration is in meters per second square, you divide by 9.8.You divide the given acceleration by the standard acceleration due to Earth's gravity. If the acceleration is in meters per second square, you divide by 9.8.
Why does second sq occurs in the unit of acceleration?
That's because you are dividing a speed by a time. In the case of constant acceleration, acceleration can be calculated as (difference in velocity) / time. In fact, that's basically how acceleration is defined. The corresponding units are (meters / second) / second.
Stages of a rocket going into space?
The stages of a rocket going into space: The first stage of a rocket is used to acquire the acceleration of a rocket. When the fuel of the first stage is exhausted ,it detaches from the rockets and drops off. The velocity at this stage becomes the initial velocity of the second stage .Now the second stage is ignited ,the rocket gains acceleration and it's velocity foes on increasing . The removal of the surplus mass contained in the first stage helps in attaining the higher velocity .When the fuel of the second stage is exhausted ,it too detached from the rocket .Finally at the third stage , the rocket starts off with the required velocity.
A rocket is launched upward with a velocity of 64 feet per second from the top of a 95-foot structure What is the maximum height attainrd by the rocket?
The rocket would attain a maximum height of 158.65 feet (63.65 feet from the top of the structure).
A 2.15 kg book is dropped from a height of 1.6 meters what is its acceleration?
If air resistance can be ignored, the acceleration is 9.82 meters per second square. Note that to get this result, neither the mass of the book, nor the height from which it is dropped, is relevant.If air resistance can be ignored, the acceleration is 9.82 meters per second square. Note that to get this result, neither the mass of the book, nor the height from which it is dropped, is relevant.If air resistance can be ignored, the acceleration is 9.82 meters per second square. Note that to get this result, neither the mass of the book, nor the height from which it is dropped, is relevant.If air resistance can be ignored, the acceleration is 9.82 meters per second square. Note that to get this result, neither the mass of the book, nor the height from which it is dropped, is relevant.
A rocket gose from 0 m per second to 560 m per second in the first 7 seconds of flight What is your acceleration?
a = m/s/s a = 560/1/7 a = 80m/s/s
If the rocket has an initial mass of 6000 and ejects gas at a relative velocity of magnitude 2000 how much gas must it eject in the first second to have an initial acceleration of 25.0?
985kg
Why do we a use the units meters per second squared when we talk about acceleration?
For every second of acceleration the velocity is increased by that acceleration.
How do you increase accelaration of a rocket in space?
F = M A whence A = F/M .Acceleration is directly proportional to the force applied to the rocket, and inverselyproportional to the rocket's mass. If you need to increase the acceleration, you havetwo choices . . . either reduce the rocket's mass, or increase the force applied to it.That means you must either toss something overboard, or else burn fuel faster.There's no other way.
If a bowling ball and a Nerf ball dropped at the same time and height what would the acceleration be?
it would be 9.8 meter per second. anything that isn't subject to air resistance(like paper) will fall at this rate for this is the acceleration of gravity,
A rocket becomes progressively easier to accelerate as it travels upward from the ground mainly because?
The rocket's acceleration is created by the net force acting on it. There are three forces acting on the rocket: the thrust provided by the engines, gravity or weight, and air resistance. The acceleration is inversely proportional to the rocket's mass. This is Newton's Second Law: (acceleration) = (net force) / (mass) We need to think about the direction of the forces. The thrust acts upward (call this positive), and both gravity and air resistance acts downward (call these negative). So we get (acceleration) = (thrust - weight - air resistance) / mass A typical rocket engine will provide constant thrust as long as the fuel lasts. But as the engine consumes fuel, expelling the exhaust products out the back of the rocket, the rocket's mass decreases. This tends to increase the rocket's acceleration since acceleration is inversely proportional to the mass. In addition to the decreasing mass, the rocket's weight decreases as it moves farther from the center of the Earth--- this effect is described by Newton's Law of Gravity. The rocket's decreasing weight tends to increase its upward acceleration. The action of air resistance is more complicated, and ordinarily we ignore air resistance in simple models just to avoid the complication air resistance gives to the problem. In the standard air resistance model, air resistance scales with the square of the rocket's speed and the air density. The rocket is moving faster and faster, but the air density is also decreasing as it rises through the atmosphere. I think we can safely say the air resistance force decreases as the rocket gains altitude, but a detailed answer illustrating precisely how this force changes would require a numerical simulation. Hope this helps!
How do you Calculate G forces with only Acceleration given?
You divide the given acceleration by the standard acceleration due to Earth's gravity. If the acceleration is in meters per second square, you divide by 9.8.You divide the given acceleration by the standard acceleration due to Earth's gravity. If the acceleration is in meters per second square, you divide by 9.8.You divide the given acceleration by the standard acceleration due to Earth's gravity. If the acceleration is in meters per second square, you divide by 9.8.You divide the given acceleration by the standard acceleration due to Earth's gravity. If the acceleration is in meters per second square, you divide by 9.8.
How can nawtons first law be derived from newtons second law?
The Second Law is Force = Mass times Acceleration. The First Law can be derived from the Second Law by setting the Focre to zero or the Acceleration to zero;. No force = no acceleration; or No acceleration = no force.
If a shoe is dropped from a height of 40m what is its speed after falling for two seconds?
Regardless of the height from which it is falling, (neglecting air resistance) it's speed will be 19.62 metres per second. (Acceleration from gravity is 9.81 metres per second squared, so after 1 second it is moving at 9.81 metres per second and after 2 seconds it is moving at 19.62 metres per second.
