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This is a relatively simple question that can be answered using simple stochiometry. If we assume a few things: a) that pure elements are reacting, b) that oxygen is in its stable diatomic form, and c) that they are reacting on a 1 to 1 mole ratio; then the math is as follows:

1 g.O2 x (1 mole O2 / 32 grams per mole) x (1 mole Ca / 1 mole O2) x (40.078 grams per mole / 1 mole Ca) = XXX.XX grams of Ca

Thus the amount of calcium that will react on a 1 to 1 mole ratio with one gram of diatomic oxygen (O2) is 1.252 grams of calcium

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