The velocities of the two bodies after the elastic collisions are given by V1=(M1-M2)U1/(M1+M2)+2M2U2/(M1+M2) V2=(M2-M1)U2/(M1+M2)+2U1M1/(M1+M2) Where, V1,V2 are the velocities of the two bodies after collision. U1,U2 are the velocities of the two bodies before colision.(U1>U2) M1,M2 are the masses of the two bodies. when the mass of two bodies are equal that is M1= M2 then V1=0+2MU2/2M=U2 V2=0+2MU1/2M=U1 Thus when two billiard balls of equal masses undergo perfectly elastic collision the velocities the two bodies are interchanged after the collision.
The force of gravity is F=G*m1*m2/r^2 G is the universal gravitation constant 6.67*10^-11 m^3kg^-1s^-2 m1, m2 are the masses of the two objects, r is the separation. The force on m1 acts in the direction of m2, and the force on m2 acts in the direction of m1.
Alright, so basically you're given: m1+m2=4.0kg, r=25m, Fg=2.5*10-10N We know that Fg=Gm1m2/r2 Using the fact that m1+m2=4.0kg, we know that m2=4.0kg-m1 So: Fg=Gm1(4.0kg-m1)/r2 =G(m1(4.0)-m12)/r2 So: (-G/r2)m12+(4G/r2)m1-Fg=0 Here we can use the quadratic formula to solve for m1 Once you have m1, just use m1+m2=4.0kg to find m2 I'll leave the actual number crunching to you. Hope this helps!
if we assume m1 (mass) and v1 (velocity) for first mass , m2 and v2 for second mass ,we have : m1 v1i + m2 v2i = m1 v1f + m2 v2f and 1/2 m1 v1i2 + 1/2 m2 v2i2 = 1/2 m1 v1f2 +1/2 m2 v2f2 i : initial f : final This is a simplified version: vf1= ((m1-m2)/(m1+m2))(v1i)+ (2m2/(mi+m2)vi2
m1 + m2 = 5 kg F = 1 x 10-8 N G = 6.67 x 10-11 N m2/kg2 r = 0.2 m F = (Gm1m2) / r2 1 x 10-8 N = (6.67 x 10-11 N m2/kg2)(m1)(5-m1) divide by 6.67 x 10-11 N m2/kg2 6 = 5m1 - m12 m12 - 5m1 + 6 = 0 (m1 - 3)(m1- 2) = 0 m1 = 3 kg m2 = 2 kg
The GCF of m2, m3, and m4 is m2.
if(m1>m2) f=m1; s=(m2>m3)?m1!m3 what its meaning of this?
M1, M2, M3, M4, M11, M20, M23, M40. The M25 encircles London.
#include<stdio.h> #include<conio.h> void main() { int rollno,m1,m2,m3,m4,m5,tot; float avg; char [20]name; clrscr(); printf("Enter the name,rollno,mark"); scanf("%d%d%d%d%d%d%s",&rollno,&m1,&m2,&m3,&m4,&m5,&name); tot=m1+m2+m3+m4+m5; avg=tot/5; printf("the avg is",avg); getch(); }
main() { int p,m1,m2,m3,m4,m5; printf("enter marks of 5 subjects"); scanf("%d%d%d%d%d",&m1,&m2,&m3,&m4,&m5)l p=(m1+m2+m3+m4+m5)/500*100; if(p>=60) printf("first"); else { if(p>=50) printf("second"); else { if(p>=40) printf("third"); else printf("fail"); } } }
because 3>2>1 ? Other than that, depends on what m1,m2 and m3 represent.
M 1
56???
The Autobahn is in Germany, not Ireland. The major motorways in Ireland are the M1, M2, M3, M4, M6, M7, M8, M9, M11, M18, M20, and M50.
So you propose two factors (day and movie). If you see one movie on one day, then you have 10 options. Below is a list of all of the options. (Day and then movie) Sat. - M1, Sat. - M2, Sat. - M3, Sat. - M4, Sat. - M5 Sun. - M1, Sun. - M2, Sun. - M3, Sun. - M4, Sun. - M5
#include#includevoid main(){float avg(int m1,int m2,int m3);clrscr();printf("\nAverage of 3 Subjects: %.2f",avg(78,85,95));getch();}float avg(int m1,int m2,int m3){return (m1+m2+m3)/3;}
M1 means less than 5% blasts and is the usual definition of a "remission" marrow. M2 means the marrow has between 5% and 25% leukemic blasts. M3 means there are more than 25% leukemic blasts.