rate = k[A], k= rate constant / of proprotion , [] =concentration. (@ = change in []concentration ,@t change in time)a A +bB-> cC from this the rate = -1/a(@[A]/@t) =-1/b(@[B]/@t) =1/c(@[C]/@t where the small letters are the coefficents . so the rate of a reaction is equal to each other when ajusted by the coeffiects . note that the reactants are negative becasue it is decreasing as products form..the basic difference of a fist order and a second is proportions.. fist is directly proportional id est concentration goes up by 2 the rate goes up by two.while second is proportional to the square.concentration goes up by two the rate goes up by 41. First-Order ReactionsA first order reaction (order = 1) has a rate proportional to the concentration of one of the reactants. A common example of a first-order reaction is the phenomenon of radioactive decay. The rate law is:rate = k[A] (or B instead of A), with k having the units of sec-12. Second-Order ReactionsA second-order reaction (order = 2) has a rate proportional to the concentration of the square of a single reactant or the product of the concentration of two reactants:rate = k[A]2 (or substitute B for A or k multiplied by the concentration of A times the concentration of B), with the units of the rate constant M-1sec-1
You can't change the subscript. The subscripts show how the elements/molecules are bonded.--------------------------------------------------------------------------------------------------------The subscripts represent the number of atoms of each element in each chemical formula-if you change the subscripts, you change the compounds the formulas are describing.Source: (e2020)
It is a number written in front of a symbol
3 and 5
+, -, coefficents, pronumerals. heaps
variables, coefficents, and constants
It is a multiplicative term that proceeds a variable, generally. For instance: 3x, the coeifficent is 3, also ax2+bx, here there are two coefficents. Notices coefficents can be intgers, fractions, decimals, irrational numbers, vectors and sometimes even fucntions themselves.
Everything to the right of the arrow is a product.
Coefficents don't have to be equal, it's just that that the number of each element or ion has to be the same on both sides
NaCl+AgNO3=NaNO3+AgCl Because all the elements in this equation have a +1 or -1 charge, no coefficents are needed
A quadratic equation in standard form is based on the model: ax2 + bx + c = 0 a, b, and c are called the coefficients. "Real coefficients" simply means that a, b, and c are real numbers (as opposed to complex numbers). For example: 5x2 - 3x +2 = 0 ... has real coefficients, while (3-2i)x2 + (-2 + 4i)x + (4 + 3i) = 0 does not.
Basically you have two different kinds of metal with different coefficents of expansion put together. As they expand it creates a curving effect because one is expanding more than the other. This drives the needle and gives the indication. http://en.wikipedia.org/wiki/Bi-metallic_strip
An equation is balanced if each atom on one side of the arrow has the exact same amount on the other side. You can balance the equation by adding coefficents in front of the element, but make sure there are the same amount. For example: if you have 3 atoms of Al on the left of the arrow, and 6 atoms of Al on the right side, all you have to do is add the number 2 as a coefficient in front of the first Al to make 6 atoms of Aluminum on each side.
Considering this as a mathematical problem rather than a chemical one, so not considering any on the contamination problems associated with diluting the acid, your solution should be made up 54% of your original acid and 46% water. An easy way of working ot the percentage of the current solution that you need is to work in decimals and divide the required percentage of HCl by the current percentage of HCl. I have included the Mathematics of this below. your current solution (call it solution A) is 37 parts hydrochloric acid and 63 parts water. So the quantity of solution A can be described as A = 0.37H + 0.63W Your 20% solution (call it solution B) is 20 parts hydrochloric acid and 80 parts water. So the quantity of B can be described as B = 0.2H + 0.8W However, B can also be descibed as an unknown percentage of A and the remaining percentage will be water if the percentage of A written in decimal form is x then the percentage of water is 1-x so B = Ax + (1-x)W Equating the two equations for B gives: 0.2H + 0.8W = Ax + (1-x)W Substituting in for A gives: 0.2H + 0.8W = x(0.37H + 0.63W) + (1-x)W 0.2H + 0.8W = 0.37xH + (0.63x +1 - x)W Equating coefficents of H 0.2 = 0.37x x = 0.2/0.37 x= 0.540540540 ... x = 0.54 (2.s.f) check this with equating W 0.8 = 0.63x + 1 - x 0.8 = 1 - x(1 - 0.63) 0.2 = x(1 - 0.63) x = 0.2/(1 - 0.63) x =0.540540540 ... x = 0.54 (2.s.f) so your solution should be made up 54% of your original acid and 46% water.