y-intercept would be 10 and x intercept would be -6
The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).
(6, 0) and (0, 8)
(3,3)
4x + 3y = 6y 4x = 3y 4/3 x = y The slope is 4/3 and the y intercept is 0.
-x + 3y = 6 3y = x 6 y = x/3 + 2 So slope = 1/3 and intercept = 2
The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).
x: x = 15 y: y = 10 z: z = -5
If the equation is 7x - 3y = 21 then (3, 0) and (0, -7).
The result will be a plane that intercepts the x-, y-, and z-axes at +9, +6, and +3, respectively.
The y-intercept is the place (or places) where x=0 . So if 'x' is 2y2+3y+1 , then all you have to do is find places where 2y2+3y+1 is zero, and those are your y-intercepts.
30 - 12 = 18
3y+5=y-25 2y=-30 y= -15