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if you increase the force , the mass remaining constant, a new rate of acceleration applies in the order a = f/m from that point (second law)
f=ma newtons 2nd law of motion where f is the net force m is mass in kg and a is acceleration in m/s^2 basically the net force is in the direction of the acceleration
2 meters = 6.561 679 79 feet If you need the mathematical eqation, set it up as a proportion: 1 meter 2 meters ---------- = ---------- 3.280 feet X feet Direct Conversion Formula2 m* 1 ft 0.3048 m = 6.56167979 ft
Newton's 2nd law state that the rate of momentum is proportional to the impressed force & the change in momentum takes place in the direction of force. Mathematically , F = dP/dt = m dv/dt + vdm/dt = m dv/dt = ma [for constant mass system dm/dt = 0]
"The rate of change of momentum is directly proportional to the impressed force and acts in the direction in which the force acts" Acceleration "a" varies directly proportional to "F" the impressed force. F = m x a a = F/m
Rate = k[A]m[B]n
They are experimentally determined exponents.
5.4 (apex)
The general form of a rate law is rate = k[A]^m[B]^n, where rate is the reaction rate, k is the rate constant, [A] and [B] are the concentrations of reactants A and B, and m and n are the respective reaction orders for A and B.
answer is 5.4 (mol/L)/s
4.5 (mol/L)/s
They are experimentally determined exponents
r=[A]m[B]n APPLEX
0.54 (mol/L)/s
59 - 60.1 m-1 s-1
The equation is called the rate law equation. For the reaction aA+bB =>cC+dD the rate law would be rate = k[A]^m[B]^n where k is the rate constant and m and n are the "order" with respect to each reactant. m and n must be determined experimentally and may or may not be the same as the coefficients a and b.
0.00117 - 0.0012 M-1s-1