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You use mole ratios for two reasons. One: To balance the number of moles to get the correct answer. Two: To finalize the cancellations of the measurements to get the answer.
Write down the Balanced reaction equation. Zn +2HCl = ZnCl2 + H2 The Molar ratios are 1:2::1:1 So one mole of Zinc requires two moles of Hydrochloric Acid for complete reaction, where both reactants are completely used. So for example if you had only 0.5 moles zinc and two moles of HCl, then zinc would be the limiting reactant , because all the zinc will be used up leaving 1 mole of HCl unreacted . The molar ratios are not equal 0.5 : 2 :: 0.5 : 0.5 (Leaving 2 - 1 = 1 mole HCl ) Conversely if you had 1 mole zinc and only one mole of HCl, then HCl would be the limiting reactant, because all the HCl would be used up leaving o.5 (Half) a mole of zinc unreacted. Similarly 1:1:: 0.5 : 0.5 leaving (1 - 0.5 = 0.5 mole zinc) It all requires the moles to be in the correct ratios.
Both sides are equal.3 x 5 = 15 The quantity (3 x 5) is equal to the number 15.2H2O --> 2H2 + O2 There are the same numbers of hydrogen and oxygen atoms on both sides of the equation. They have just been rearranged.
representative particles,moles, and mass.
ok well standard temperature and pressure is stp 22.4 litres per mole of gas. first write a balanced chemical equation 2C + 02 ------> 2CO then write mole ratios 2C + 02 ------> 2CO 2 : 1 : 2 using gay lussacs law and avogadros hypothesis we know that the same volumes of gases in same conditions are mole ratios (only works with gases however) so therefore the volume of CO gas produced will be 2 x that of the volume of oxygen gas (because ratio of O2 gas to CO gas is 1:2) =2x2.24 =4.48 litres of CO gas produced then the moles can be worked out by - number of moles = volume given/volume of 1 mole at STP = 4.48/22.4 =0.2 moles roughly i think. Answer: 1.20 g C is 1/10 mole of C 2.24 liters of O2 is 1/10 mole of O2So when equal volumes molar anounts of C and O2 react: C (1 mole)+ O2(1 mole)-> CO2 (1 mole) (No CO is produced) With the given initial amounts 1/10 mole (2.24 liters) of CO2 would be producedIf oxygen were limited all C could be converted to CO. This would rturn the inital amount of C (1,2 g) and 1.12 liters of O2 into 1/10 mole of CO (2.24 liters)
Mole Ratios
At constant temperature and pressure the ratios are equal.
To convert from one substance to another
Coefficients
mole ratios
Necause the 2 indicators have different PHs level
Represents the mole ratios between any two substance
No they give mole ratios. A mole is much like a dozen, a dozen is 12 while a mole is 6.02*10^23. This means that 1 mole of a substance represents 6.02*10^23 molecules of that substance.
You use mole ratios for two reasons. One: To balance the number of moles to get the correct answer. Two: To finalize the cancellations of the measurements to get the answer.
Write down the Balanced reaction equation. Zn +2HCl = ZnCl2 + H2 The Molar ratios are 1:2::1:1 So one mole of Zinc requires two moles of Hydrochloric Acid for complete reaction, where both reactants are completely used. So for example if you had only 0.5 moles zinc and two moles of HCl, then zinc would be the limiting reactant , because all the zinc will be used up leaving 1 mole of HCl unreacted . The molar ratios are not equal 0.5 : 2 :: 0.5 : 0.5 (Leaving 2 - 1 = 1 mole HCl ) Conversely if you had 1 mole zinc and only one mole of HCl, then HCl would be the limiting reactant, because all the HCl would be used up leaving o.5 (Half) a mole of zinc unreacted. Similarly 1:1:: 0.5 : 0.5 leaving (1 - 0.5 = 0.5 mole zinc) It all requires the moles to be in the correct ratios.
Both sides are equal.3 x 5 = 15 The quantity (3 x 5) is equal to the number 15.2H2O --> 2H2 + O2 There are the same numbers of hydrogen and oxygen atoms on both sides of the equation. They have just been rearranged.
In stoichiometric mole to mole conversions you use the ratio of the coefficients from a balanced equation in combination with information given from a problem or procedure. You use the ratios to cross multiple and divide to find the unknown quantity.