Want this question answered?
The wavelength is inverse to the frequency, meaning the frequency in this case will increase.
when you increase the frequency, then the wavelength decreases. :)
No, the frequency decreases as the wavelength lengthens. The shorter the wavelength the higher the frequency.
Wavelength is inversely proportional to Frequency. Wavelengths increase as Frequency decreases.
No. Greater frequency = less period.
The wavelength is inverse to the frequency, meaning the frequency in this case will increase.
If you increase the mass of an object, the potential energy will increase.
Increase the energy in general.
when you increase the frequency, then the wavelength decreases. :)
No, it doesn't become "larger" - the peak potential is always the same - it is a digital signal. Stronger stimulus will cause the nerve cell to fire more often - therefore stimulus strength is translated as action potential frequency.
frequency x wavelength = speedSo, if you increase frequency, the wavelength decreases, and vice versa.
Increase decrease. The frequency MUST decrease.
micro economic policy to increase S.A exports potential micro economic policy to increase S.A exports potential micro economic policy to increase S.A exports potential micro economic policy to increase S.A exports potential micro economic policy to increase S.A exports potential micro economic policy to increase S.A exports potential micro economic policy to increase S.A exports potential
when the frequency is low , energy will be obviously low. To increase the energy of the signal we need to increase the frequency. This is achieved by multiplying the message signal with the carrier signal (with high frequency).
The threshold may increase until a certain point in which the refractory period is so short that it will not allow for stimulus. Toby G Attending EMT-P school.
Wavelength is inversely proportional to Frequency. Wavelengths increase as Frequency decreases.
No, the frequency decreases as the wavelength lengthens. The shorter the wavelength the higher the frequency.