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The genders of pronouns are:
- pronouns for a male (he, him, you, they, them, his, himself)
- pronouns for a female (she, her, you, they, them, hers, herself)
- neuter (it, they, them)
The genders of nouns are:
- a noun for a male (boy, uncle, king, stallion, peacock, ram)
- a noun for a female (mother, sister, duchess, mare, peahen, ewe)
- common gender nouns (teacher, parent, neighbor, pilot, author, person)
- neuter nouns (fence, carrot, street, airplane, rock, pencil, paper, pool)
What else can I help you with?
How many ways can you select 3 people out of 10?
240
How many ways can a dinner patron select 3 appetizers and 2 vegetables if there are 6 appetizers and 5 vegetables on the menu?
Oh, what a delightful question! To find the total ways a dinner patron can select 3 appetizers out of 6, we use combinations, which is like a recipe for choosing items without regard to the order. So, the dinner patron can choose 3 appetizers out of 6 in 20 ways. Similarly, they can choose 2 vegetables out of 5 in 10 ways. So, the total ways to select 3 appetizers and 2 vegetables is 20 * 10 = 200 ways. Isn't that just lovely?
How many ways can you select 3 marbles from a jar containing 10 different colored marbles?
To select 3 marbles from a jar containing 10 different colored marbles, you can use the combination formula ( C(n, r) = \frac{n!}{r!(n-r)!} ). Here, ( n = 10 ) and ( r = 3 ). Thus, the number of ways to select the marbles is ( C(10, 3) = \frac{10!}{3!(10-3)!} = \frac{10 \times 9 \times 8}{3 \times 2 \times 1} = 120 ). Therefore, there are 120 different ways to select 3 marbles.
How many possible combinations of 1 shirt and 1 pair of shorts can be made from 6 shirts and 3 pairs of shorts?
We select 1 shirt out of 6 shirts in (6 choose 1) ways or 6 ways. Then, we select 1 out of 3 pairs of shorts in (3 choose 1) or 3 ways. Therefore, the possible combinations of a shirt and a pair of shorts is 6 * 3 = 18 possible combinations.
How many ways can I select a committee of 3 people from 10 people?
To select a committee of 3 people from 10, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). Here, ( n = 10 ) and ( k = 3 ). This gives ( C(10, 3) = \frac{10!}{3!(10-3)!} = \frac{10 \times 9 \times 8}{3 \times 2 \times 1} = 120 ). Therefore, there are 120 ways to select a committee of 3 people from 10.
How many ways can 4 finalists be selected from 50 people?
You have 50 ways to select the first.For each of those 50, you have 49 ways to select the second.Only 49 ways, because for each of the 50, there are only 49 left to select from.That's 50 x 49 ways to select the first and the second.For each of those 50 x 49 ways, you have 48 ways to select the third.That's 50 x 49 x 48 ways to select the first, second and third.For each of those 50 x 49 x 48 ways, you have 47 ways to select the fourth.That's 50 x 49 x 48 x 47 ways to select the first, second and third and fourth.But if it doesn't matter what order they are selected in, the same four people have been counted multiple times. For example, if people A, B, C and D have been selected, we will have counted A, B, C and D as one way, and D, C, B and A as another, B, D, A and D as another. In fact, there are 4 x 3 x 2 x 1 ways of counting any four people.So if order does not matter, there are (50 x 49 x 48 x 47) / (4 x 3 x 2 x 1) ways.How many ways can 5 finalists be selected from 100 people?
What are the genders of Angelina Jolie and Brad Pitt's children?
They have 3 boys and 3 girls.
How many ways can an IRS auditor select 3 of 11 tax returns for an audit?
39916800/241920=165 would be the math answer.
How many ways can you select three numbers from 1 2 3 4 5 6 7 8 so that the numbers could represent the measures of the sides of a triangle?
There are 22 ways.
I am taking a vacation and plan to read 3 books while I'm gone I have 25 books to choose from How many ways can I select the 3 books to take on vacation?
2300
You fantasize about girls and guys are you bi?
few better ways of tell that you're bi than fantasizing about both genders.
How many ways can a student select 7 questions from an exam containing 11 questions if he must answer the last question?
If he must answer the last question, he effectively needs to select 6 from 10. This can be done in 10C6 = 10*9*8*7/(4*3*2*1) = 210 ways.
