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This is the part of an incandescent bulb called the filament. Incandescent bulbs are obsolescent and will probably phase out over the next few decades.
The answer is no. However, it will run out of electricity if you put a lot of energy into the light bulb when you switch it on. Thank you for asking young fellow person who is unknown to me. -Your fellow friend
Light bulb filaments glow rather than burn because of the lack of oxygen within the vacuum of the bulb. Over time, the heating and contracting of the filament and the glass surrounding it creates a leak in the base of the bulb causing the vacuum to be lost and allowing oxygen to enter the bulb. It is during the contracting phase, which happens as the bulb cools after being turned off, that eventually the seal is lost. When this happens, oxygen is allowed to enter and the next time the bulb is turned on, the filament, now exposed to the oxygen, burns out.
Circuit breakers can often trip when a light bulb fails just at the point when you switch on the light. The reason it happens is that, in normal use, the bulb's filament gets thinner and thinner and more and more brittle over time.Eventually it is about to fail - also known as "burn out" - but it doesn't usually do it whilst it is still burning because it's resistance is at its highest when it is hot and "lit", so it is taking the least amount of current whilst it is "on".But then, if you switch that bulb off as normal, when you next come to switch it on its filament will be cold and its resistance will be lower than when it was hot. At the point of switching it on it draws a higher starting current for the last time but then, as the filament finally "snaps", the "flying ends" of the snapped filament can sometimes momentarily short-out the hot and neutral filament feed wires, taking a very high current which trips the circuit breaker!Any incandescent light bulb will draw a higher starting current when you first switch it on because, when cold, the filament resistance is at its lowest point. The bulb soon heats up to its normal running temperature at which point the current settles to its normal running current which is lower than its cold starting current.But in the case of a bulb that has been used for near to - or more than - its designed number of hours, then it is much more likely to fail in a way that causes the circuit breaker to trip, as has been described above.Provided they have not been "knocked or dropped" at some time during their life - which would significantly shorten their actual expected "life" because of mechanical damage to the filament - ordinary incandescent bulbs are rated for only about 1000 hours of actual use. More expensive "long-life bulbs are available that are rated at 2000 hours.A different answerIf your home is new and has the new type of arc-fault breakers, this occurs from time to time when the filament in the bulb blows because the failing bulb causes an arc and the breaker does what it was designed to do: stop the arc.
Thomas Edison invented the a long-lasting, practical electric light bulb.He had experimented with thousands of different filaments to find just the right materials to glow well and be long-lasting. In 1879, Edison discovered that a carbon filament in an oxygen-free bulb glowed but did not burn up for 40 hours. Edison eventually produced a bulb that could glow for over 1500 hours.For additional information about the light bulb - see Related Question below.
Answer:The filament inside the light bulb reaches over 3000 degree Celsius.
A light bulb glows because of a very fine wire inside the glass bulb called a 'filament'. When an electrical current is put through the filament, assuming the voltage is high enough, it will begin to heat up and glow because such a small wire cannot handle the flow of electrons and has to discharge them through heat and light. Also if you put to much voltage in it will heat up the filament too much and melt it. Incandescent (filament) light bulbs fail over time because they slowly lose small amounts of wire until the filament breaks and stops glowing.
It can if it is a dual filament bulb as found on most US. makes. The brake light filament can short over to the tail light filament inside the bulb and when the brakes light is activated, all the tail lights and front marker lights will light also, probably blowing fuses.
Resistive Heating, as current passes through the filament power is dissipated from the filament in the form of heat, they are made of Tungsten which has a melting point of 3380 degree Celsius. And since the interior of the bulb contains very little to no oxygen, usually filled with argon or similar type gas. The filament cannot burn, but will degrade over time to the point where it "burns out" but in reality the filament just breaks
This is the part of an incandescent bulb called the filament. Incandescent bulbs are obsolescent and will probably phase out over the next few decades.
A light bulb works by passing electricity through a long, thin piece of metal that is called a filament. The electricity heats up the filament much like an electric stove heats up its elements. The heat, through black body radiation, causes the filament to emit light. But, the heat also stretches and thus weakens the filament. Over time the weakening will break the filament along the heated portion and this is called "burning out" in common language.
The answer is no. However, it will run out of electricity if you put a lot of energy into the light bulb when you switch it on. Thank you for asking young fellow person who is unknown to me. -Your fellow friend
As an incandescent light bulb is used, tungsten slowly evaporates from the filament causing it to get thinner. When it gets too thin it can no longer carry the current and part of it melts causing the bulb to blow out.
The main component of an incandescent light bulb is the metal filament (the spiral). The filament is heated up by the AC current, when the lamp is turned on. The heat excites the metal ions so much that they radiate energy in the form of light. The spectrum of the radiation spans from visible (the warm light you can see) to invisible (infrared, which is heat). Heat is really infrared emission, which is still 'light' in physics terms.
Light bulb filaments glow rather than burn because of the lack of oxygen within the vacuum of the bulb. Over time, the heating and contracting of the filament and the glass surrounding it creates a leak in the base of the bulb causing the vacuum to be lost and allowing oxygen to enter the bulb. It is during the contracting phase, which happens as the bulb cools after being turned off, that eventually the seal is lost. When this happens, oxygen is allowed to enter and the next time the bulb is turned on, the filament, now exposed to the oxygen, burns out.
To avoid oxidation of the filament material (which will reduce the life and darken the glass bulb) at high temperature. The bulb is filled with any inert gas- inert means non-reacting, like argon, neon etc, these non-reacting gasses do not have any free electrons in their valence shell to combine with the filament material so how much ever it gets hot the filament may break due to over heating but will not react and get oxidized, and basically oxidation means burning! so when you read the history of the bulb you can see the first ever filament the carbon filament burned out quickly because carbon is C and oxygen is O so C+2O = CO2 so as it gets up it burned out and gave out sooth which is practically very fine carbon ( early darkening of the bulbs ) but tungsten improved everything. some times the inside of the bulb is just vacuum no inert gas or any gas, that can also avoid oxidation... that's why when you break a bulb it makes such a ' POP ' sound due to air rushing in when the vacuum is broken!
An incandescent light bulb is essentially a wire through which current flows. The wire gets heated up and glows giving off light. According to Ohm's Law Volts = Current x Resistance. In this case resistance is the resistance of the filament. Since in a residence the voltage remains more or less constant, the way more energy would be use is if more current passed through the filament. If the resistance of the filament decreased then the current would increase. Not sure how an aging bulb would have a decreased resistance. If this were somehow possible such that the composition of the filament changes and reduced resistance then the energy required to operate the bulb would increase.