Amperes is not constant like voltage. You can have .01 amps or 1200amps on a wire. Basic sizes of cable and their amp limits (for residential usage): 14ga. 15amps, 12ga. 20amps, 10ga 30 amps. It doesn't matter if its on 110V or 220V
Wire is sized by the amperage that it will carry. 5 kW is 5000 watts. The equation to find watts is W = Amps x Volts. The equation to find amps is Amps = Watts/Volts. As you can see a voltage is needed to calculate the amperage. Once the amperage is stated, the wire size can be given for that particular amperage.
In North America it takes two "hot" wires to obtain 240 volts.
Wire size is based on the amperage of the connected load. Without that amperage an answer can not be given.
Any voltage can be applied to any size wire. It is the load amperage that the wire must be sized for. The larger the amperage, the larger the wire size must become.
Wire size is based on the amperage of the load. Without knowing what the motors's full load amperage is, an answer can not be given.
Don't!
Fuses are based upon the size of the wire of the circuit that it is to protect. The wire is sized by the amperage of the connected amperage load of the circuit.
The amperage flowing through a wire is directly related to the load placed on the circuit, and has nothing to do with wire size, except that a larger wire will carry more amperage. Increasing wire size will not lower amperage but will allow the circuit to carry more amperage if the breaker is also increased in size. No. Ohm's law tells us that V = IR. For a given load, R is constant, and thus the only way to reduce current is to increase voltage.
The voltage of the solar panel is less important than the total amperage. Proper wire size is determined by amperage that will be going through the wire. Wire INSULATION determines the voltage that a wire can carry.
Wire size is based on the amperage drawn. To find the amperage, the voltage must be stated. Use this formula to find the amperage. I = W/E. Amps = Watts/ Volts. Once you have the amperage, restate your question using the new found amperage or state the voltage that supplies the lights.
Wire size needed depends on amperage, not watts. If you know the voltage of the power supplied you can calculate the amperage using this form of the "power formula":A = W / VThen there are tables that tell the amperage each wire gauge is capable of carrying. Just select the gauge that has the amperage rating just larger than you calculated.
Wire size is governed by amperage not voltage. Voltage is an insulation factor when talking about wire. Add up the amperage of fixtures you want in the circuit. Once that is found then the size of the wire can be calculated.