Being born with six fingers is actually a dominant trait and the probability of the children would be 75% with six
fingers and 25% with five fingers if both parents were heterozygous for that trait. If both parents were homozygous dominant for that trait then there is a 100% probability of the children being born with six fingers.
It will depend on the genotype of the parents.
If both parents have the same genotype, say BB - then all of their children should also be BB.
If both parents are heterozygous, Bb - then 50% of their children should also be heterozygous (Bb), 25% BB and 25% bb.
If one parent is BB and the other bb - then all of their children will be heterozygous (Bb).
If the trait for six fingers is dominant then the odds are 3/4, if the trait is recessive then the odds are 1/4
50%
1/2
25%
9:3:3:1 The probability of having both recessive traits is 1:16.
It will be all about the gains and shreins
About 50%, if there are no other genes available.
no because his children are heterozygous not homozygous, which is the prerequisite for being purebred
1/8 or 12.5%
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
There are 3 probabilities: dominant homozygous, recessive homozygous, or heterozygous.
Impossible. You can only be heterozygous or homozygous, not both.
25%
75%
25%
3:4 or 75%
9:3:3:1 The probability of having both recessive traits is 1:16.
It is a 75% chance that the seeds will be round.
both parents could be A heterozygous or one A heterozygous and the other O
false