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If dad has freckles and is homozygous and mom has freckles and is heterozygous what phenotypes and genotypes can you expect their offspring?
Alright, I suppose I will do your homework for you.. Here is your punnet square: F F F FF FF f Ff ff Therefore, 3/4, or 75%, offspring will have the phenotype of having freckles, and 1/4, or 25% will have the phenotype of no freckles. And 2/4, or 50%, of the offspring will have the genotype for homozygous for freckles, 1/4, or 25%, of the offspring will carry a heterozygous trait for freckles, and 1/4, or 25%, of the offspring will have the phenotype for homozygous no freckles.
In crossing a homozygous recessive with a heterozygote what is the chance of getting a homozygous recessive phenotype in the F1 generation?
1/2 or 50%. The homozygous recessive gentoype contains two recessive alleles for the gene for a trait. So the homozygous recessive individual can pass on only recessive alleles to an offspring. The heterozygous individual has one dominant and one recessive allele for the gene for a trait. So the heterozygous individual can pass on either a dominant or a recessive allele to an offspring. So if an offspring inherits a recessive allele from the heterozygous parent, along with the recessive allele from the homozygous recessive parent, it will have the homozygous recessive genotype and phenotype.
What are the possible offspring outcomes if parent 1 Tt crosses with parent 2 tt?
The possible offspring outcomes of this cross would be 50% Tt (heterozygous) and 50% tt (homozygous recessive).
What are the genotype and phenotype ratios in offspring from two heterozygous parents?
The genotype ratio is 1:2:1 (1 homozygous dominant, 2 heterozygous, 1 homozygous recessive) and the phenotype ratio is 3:1 (3 individuals showing the dominant trait, 1 individual showing the recessive trait).
What is the probability of obtaining a dominant phenotype from self-fertilization of a heterozygous individual is?
The probability of obtaining a dominant phenotype from self-fertilization of a heterozygous individual is 75%. This is because in a heterozygous individual, there is a 50% chance of passing on the dominant allele and a 50% chance of passing on the recessive allele. With self-fertilization, the possible combinations are: 1 dominant allele (25%), 2 dominant alleles (50%), and 1 recessive allele (25%). Dominant phenotype will be expressed if there are one or more dominant alleles present.
What is the probability of 2 heterozygous individuals producing a heterozygous recessive offspring?
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
What is the probability of 2 heterozygous individuals producing a homozygous recessive offspring?
25%
Show the cross between 2 heterozygous dogs. black fur B is dominant to brown fur b?
The Punnett square for crossing two heterozygous dogs (Bb x Bb) would result in a 25% chance of offspring with homozygous dominant black fur (BB), a 50% chance of offspring with heterozygous black fur (Bb), and a 25% chance of offspring with homozygous recessive brown fur (bb).
What is a homozygous dominant offspring are?
Offspring that posses two different forms of the same gene. These are called alleles.
What probability two offspring in heterozygous cross will have same genotype?
In a heterozygous cross (e.g., Aa x Aa), the possible genotypes of the offspring are AA, Aa, and aa. The probability of having two offspring with the same genotype can be calculated as follows: the probabilities of each genotype are 1/4 for AA, 1/2 for Aa, and 1/4 for aa. Thus, the probability that both offspring have the same genotype is the sum of the probabilities of each genotype occurring twice: (1/4 * 1/4) + (1/2 * 1/2) + (1/4 * 1/4) = 1/16 + 1/4 + 1/16 = 5/16. Therefore, there is a 5/16 chance that both offspring will have the same genotype.
What is the probability that two heterozygous parents would have an offspring that produced round seeds?
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
What is a probability of 2 Rh plus heterozygous have 4 Rh- children?
1/8 or 12.5%
What is the apporoximate probability that a human offspring will be female?
1/2.
What is the probability that a cross between a hybrid pea plant with round seeds and one with wrinkled seeds will produce offspring with wrinkled seeds?
The probability that an offspring will have wrinkled seeds is 2 in 4 or 50%
If dad has freckles and is homozygous and mom has freckles and is heterozygous what phenotypes and genotypes can you expect their offspring?
Alright, I suppose I will do your homework for you.. Here is your punnet square: F F F FF FF f Ff ff Therefore, 3/4, or 75%, offspring will have the phenotype of having freckles, and 1/4, or 25% will have the phenotype of no freckles. And 2/4, or 50%, of the offspring will have the genotype for homozygous for freckles, 1/4, or 25%, of the offspring will carry a heterozygous trait for freckles, and 1/4, or 25%, of the offspring will have the phenotype for homozygous no freckles.
What is the probability that the children will be heterozygous?
Being born with six fingers is actually a dominant trait and the probability of the children would be 75% with six fingers and 25% with five fingers if both parents were heterozygous for that trait. If both parents were homozygous dominant for that trait then there is a 100% probability of the children being born with six fingers.
In crossing a homozygous recessive with a heterozygote what is the chance of getting a homozygous recessive phenotype in the F1 generation?
1/2 or 50%. The homozygous recessive gentoype contains two recessive alleles for the gene for a trait. So the homozygous recessive individual can pass on only recessive alleles to an offspring. The heterozygous individual has one dominant and one recessive allele for the gene for a trait. So the heterozygous individual can pass on either a dominant or a recessive allele to an offspring. So if an offspring inherits a recessive allele from the heterozygous parent, along with the recessive allele from the homozygous recessive parent, it will have the homozygous recessive genotype and phenotype.
